a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
b = a + [nil]
p a #=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
p b #=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, nil]
Is there any other Rubyist way to get the b
array from a
array?
a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
b = a + [nil]
p a #=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
p b #=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, nil]
Is there any other Rubyist way to get the b
array from a
array?
b = a.push nil
Walter
Oh, duh, never mind, that pushes it onto a also.
Walter
Okay, this works:
1.9.3-p392 :009 > a
=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
1.9.3-p392 :010 > b = [a, nil].flatten
=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, nil]
1.9.3-p392 :011 > b
=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, nil]
1.9.3-p392 :012 > a
=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
Colin L. wrote in post #1110051:
On 24 May 2013 14:56, Love U Ruby [email protected] wrote:
a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
b = a + [nil]
p a #=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
p b #=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, nil]Is there any other Rubyist way to get the
b
array froma
array?If what you really want is to add a nil element to a then you can just
do
a << nil
or, as Walter suggested
a.push nilColin
@Colin - I don’t want to modify the array a
. Thus push
and <<
can’t be helpful.
On 24 May 2013 16:20, Love U Ruby [email protected] wrote:
do
a << nil
or, as Walter suggested
a.push nilColin
@Colin - I don’t want to modify the array
a
. Thuspush
and<<
can’t be helpful.
OK, I thought it was worth checking. Often people do not ask the
question that they should.
Colin
On 24 May 2013 14:56, Love U Ruby [email protected] wrote:
a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
b = a + [nil]
p a #=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
p b #=> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, nil]Is there any other Rubyist way to get the
b
array froma
array?
If what you really want is to add a nil element to a then you can just
do
a << nil
or, as Walter suggested
a.push nil
Colin
On Fri, May 24, 2013 at 10:33 AM, Paul J. [email protected] wrote:
a = [1,2,3,4,5,6,7,8,9,10]
b= a.reverse.reverse
Can’t tell if you are trolling or if you think that’s actually a good
idea. How about just doing:
a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
b = a.dup
a = [1,2,3,4,5,6,7,8,9,10]
b= a.reverse.reverse
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