Find previous & next in array


#1

hi, anyone know how to do this?

basically i’ve got an array of items

a = [‘a’,‘b’,‘c’,‘d’]

now given i can find the position of say ‘c’ using .index(‘c’), how do i
get the positions of the ones previous & next to it.

a recursive routine would probably do it, but looking for something more
flash

any ideas?


#2

2009/5/14 John G. removed_email_address@domain.invalid

flash

any ideas?

Posted via http://www.ruby-forum.com/.

a[a.index(:c)-1] or a[a.index(:c)+1]?


#3

Boby had it almost right!

instead of:

a[a.index(:c)+1]

it is:

a[a.index(‘c’)+1]

:slight_smile:

On Wed, May 13, 2009 at 11:48 PM, Boby Selamet Hartono


#4

2009/5/14 John G. removed_email_address@domain.invalid:

flash

any ideas?

Depends on what you need to do. Do you need those indexes or do you
only need access to those elements?

There are a few variants, but the nice ones aren’t really safe against
edge cases (first and last element):

irb(main):004:0> a = [‘a’,‘b’,‘c’,‘d’]
=> [“a”, “b”, “c”, “d”]
irb(main):005:0> i = a.index(‘c’) and a[i-1 … i+1]
=> [“b”, “c”, “d”]
irb(main):006:0> a[a.index(‘c’) - 1, 3] rescue nil
=> [“b”, “c”, “d”]
irb(main):007:0> i = a.index(‘a’) and a[i-1 … i+1]
=> []
irb(main):008:0> a[a.index(‘a’) - 1, 3] rescue nil
=> [“d”]

The safest is probably

i = a.index(‘c’)

if i
predecessor = i > 0 ? a[i -1] : nil
successor = a[i + 1] # safe!
end

Or as a variant

i = a.index(‘c’) and begin
predecessor = i > 0 ? a[i -1] : nil
successor = a[i + 1] # safe!
end

Kind regards

robert


#5

2009/5/14 Joshua C. removed_email_address@domain.invalid

:slight_smile:

a = [‘a’,‘b’,‘c’,‘d’]

Posted via http://www.ruby-forum.com/.

a[a.index(:c)-1] or a[a.index(:c)+1]?


Tidak ada yang lebih baik dari kembali ke asal
Nothing can be better than back to the roots

It was a copy from my irb. I’m use symbols as objects in my array. I’ve
never use index method but since I figure out that method returns an
Integer
I think it would be something like that (thanks to irb). I’m a newbie
and
just joining this ML yesterday :-).


#6

Bobby, I am new too, so I might be missing something as well.

I tried your method first, and when I tried to do the symbol in irb it
gave
an error. Maybe you have settings I do not?


#7

The safest is probably

i = a.index(‘c’)

if i
predecessor = i > 0 ? a[i -1] : nil
successor = a[i + 1] # safe!
end

Or as a variant

i = a.index(‘c’) and begin
predecessor = i > 0 ? a[i -1] : nil
successor = a[i + 1] # safe!
end

Kind regards

robert

thanks Robert, i was trying to build up a little function to find the
prev/next elements in an array, thanks to your help it’s sorted;
couldn’t find a solution online. appreciate it all.

John.