Filter Simple-XML output

Ruby
1

Hello,

I’m absolutely new to ruby and I’m trying to parse a XML structure and
filter it for some attributes. The XML looks like this:

I want to check if the status attribute is OK. So far I have written
this code:

#!/usr/bin/ruby -w

require ‘rubygems’
require ‘net/http’
require ‘xmlsimple’

url = URI.parse(“URL to XML”)
req = Net::HTTP::Get.new(url.path)
res = Net::HTTP.start(url.host, url.port) {|http|
http.request(req)
}

sysinfodoc = XmlSimple.xml_in(res.body)

sysinfodoc[“machines”][0][“machine”][0].each do |status|
p status
end

which gives me the following output:
[“name”, “localhost”]
[“vizqlserver”, [{“worker”=>“localhost:9100”, “status”=>“OK”},
{“worker”=>“localhost:9101”, “status”=>“OK”}]]
[“dataengine”, [{“worker”=>“localhost:27042”, “status”=>“OK”}]]
[“repository”, [{“worker”=>“localhost:8060”, “status”=>“OK”}]]
[“webserver”, [{“worker”=>“localhost:80”, “status”=>“OK”}]]
[“backgrounder”, [{“worker”=>“localhost:8250”, “status”=>“OK”}]]
[“serverwebapplication”, [{“worker”=>“localhost:8000”, “status”=>“OK”},
{“worker”=>“localhost:8001”, “status”=>“OK”}]]
[“dataserver”, [{“worker”=>“localhost:9700”, “status”=>“OK”},
{“worker”=>“localhost:9701”, “status”=>“OK”}]]

How can I filter this so I get just the status for every machine child?
Or is this the wrong approach alltogether?

EDIT:

I have changed my script a bit and now it kinda starts outputting what
I’m looking for.

#!/usr/bin/ruby -w

require ‘rubygems’
require ‘net/http’
require ‘xmlsimple’

url = URI.parse(“URL to XML”)
req = Net::HTTP::Get.new(url.path)
res = Net::HTTP.start(url.host, url.port) {|http|
http.request(req)
}

sysinfodoc = XmlSimple.xml_in(res.body)

sysinfodoc[“machines”][0][“machine”][0].each do |status|
p status[1][0]
p status[1][1]
end

Output:
{“worker”=>“localhost:8060”, “status”=>“OK”}
nil
{“worker”=>“localhost:27042”, “status”=>“OK”}
nil
{“worker”=>“localhost:9100”, “status”=>“OK”}
{“worker”=>“localhost:9101”, “status”=>“OK”}
{“worker”=>“localhost:8000”, “status”=>“OK”}
{“worker”=>“localhost:8001”, “status”=>“OK”}
{“worker”=>“localhost:8250”, “status”=>“OK”}
nil
{“worker”=>“localhost:9700”, “status”=>“OK”}
{“worker”=>“localhost:9701”, “status”=>“OK”}
{“worker”=>“localhost:80”, “status”=>“OK”}
nil
108
111

How do I get rid of the nils and the Fixnums?

Regards,
Fabian

2

Quite simple, inspect the object before puts() and do whatever you want
to do. Example:

here ! is denoting false or nil

if(!status[1][0]) do

do something

elsif(status[1][0].class == Fixnum)

do something

else

and so on

end