File upload error(can't convert Tempfile into String)

i tried a method to implementa file uploader by using amethod below

this is ma controlller method to upload

def save_imports
Contactslist.save(params[:list])
render :text => “File uploaded successfully”

this is ma view file

.remote

  • form_for(@list, :url=> save_imports_list_path(@list, :format =>
    “js”), :html => { :multipart => true, :target => “uploading”, :onsubmit
    => “$('list_submit).disabled = true” }) do |f|
    = link_to_close edit_list_path(@list)
    .section
    %small
    #{t :add_contacts_from_file}
    %table{ :width => 500, :cellpadding => 0, :cellspacing => 0 }
    %tr
    %td{ :valign => :top }
    .label.top.req #{t :upload_new}:
    =f.file_field :uploads, :style => “width:240px”

    .buttonbar
    = f.submit “#{t:save_contacts}”, :onclick => “this.disabled =
    true”
    #{t :or}
    = link_to_cancel edit_list_path(@list)

i created amodel contact list and nclude amethod as given below

class Contactslist < ActiveRecord::Base
def self.save(upload)
name = upload[‘uploads’]
puts name
directory = “public/avatars”
# create the file path
path = File.join(directory, name)
# write the file
File.open(path, “wb”) { |f| f.write(upload[‘uploads’].read) }
end
end
when i tried to upload a file its showing errors as

TypeError in ListsController#save_imports

can’t convert Tempfile into String

can anyone help.is there any fault in this method?actually i wanted
toupload this files into a table callled contactslists or to move to
a folder in my application pls provide help

Hey Tony,

You just need

name = upload[‘uploads’].original_filename

instead of

name = upload[‘uploads’]

/Lasse

2010/3/26 Tony A. [email protected]

Lasse B. wrote:

Hey Tony,

You just need

name = upload[‘uploads’].original_filename

instead of

name = upload[‘uploads’]

/Lasse

2010/3/26 Tony A. [email protected]

thanks a lot its working now

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