In Given Figure, find tan P – cot R.

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#### Solution

Applying Pythagoras theorem for ΔPQR, we obtain

PR^{2} = PQ^{2} + QR^{2}

(13 cm)^{2} = (12 cm)^{2} + QR^{2}

169 cm^{2} = 144 cm^{2} + QR^{2}

25 cm^{2} = QR^{2}

QR = 5 cm

`tan P = ("Side opposite to"angle P)/("Side adjacent to"angleP) = (QR)/(PQ)`

= 5/12

`cot R = ("Side opposite to"angle R)/("Side adjacent to"angleR) = (QR)/(PQ)`

= 5/12

tan P - cot R = ` 5/12 - 5/12 = 0`

Concept: Trigonometric Ratios

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