Say I have a phone number “(555) 555-5555” and I want to extract the
numbers from it. What’s the most succinct way to do this? E.g.:
old_num = “(555) 111-5555”
new_num = “5551115555”
old_num = “555-666-7777”
new_num = “5556667777”
On 9/25/07, eggie5 [email protected] wrote:
Hi,
I would try
new_num = old_num.scan(/\d/).join(‘’)
Hope that does what you want
Nick
eggie5 schrieb:
Say I have a phone number “(555) 555-5555” and I want to extract the
numbers from it. What’s the most succinct way to do this? E.g.:old_num = “(555) 111-5555”
new_num = “5551115555”old_num = “555-666-7777”
new_num = “5556667777”
Regexp and gsub is an answer.
old_num = “(555) 111-5555”
p old_num.gsub(/[^0-9]/, ‘’)
==> “5551115555”
old_num = “555-666-7777”
p old_num.gsub(/[^0-9]/, ‘’)
==> “5556667777”
BR Phil
From: David A. Black [mailto:[email protected]]
#Don’t forget \D:
old_num.gsub(/\D/, “”)
arggh, why do i always forget the bigcases 
anyway, fr now on if i think of reverse cases, think of \D-black 
thank you and kind regards -botp
From: Nicholas Clare [mailto:[email protected]]
new_num = old_num.scan(/\d/).join(‘’)
lose this ^^
irb(main):003:0> old_num.scan(/\d/).join
=> “5551115555”
also,
irb(main):014:0> old_num.gsub(/[^\d]/,“”)
=> “5551115555”
irb(main):015:0> old_num.tr(“^0-9”,“”)
=> “5551115555”
irb(main):018:0> old_num.delete(“^0-9”)
=> “5551115555”
irb(main):025:0> old_num.split(/[^\d]/).join
=> “5551115555”
i’d hope that ruby-doc can doc such related methods… something like
documenting “The Many-Ways” of ruby…
kind regards -botp
On 9/25/07, Peña, Botp [email protected] wrote:
From: David A. Black [mailto:[email protected]]
#Don’t forget \D:
old_num.gsub(/\D/, “”)
I always wanted try the benchmark stuff, and this seemed like a good
opportunity :-).
cat remove_nondigits.rb && ruby remove_nondigits.rb
remove_nondigits.rb
25 September 2007
require ‘benchmark’
n = 100_000
old_num = “(555) 55-555-55”
Benchmark.bmbm do |x|
x.report(“scan”) do
n.times {old_num.scan(/\d/).join}
end
x.report(“gsub”) do
n.times {old_num.gsub(/[^\d]/,“”)}
end
x.report(“gsub2”) do
n.times {old_num.gsub(/\D/, “”)}
end
x.report(“tr”) do
n.times {old_num.tr(“^0-9”,“”)}
end
x.report(“delete”) do
n.times {old_num.delete(“^0-9”)}
end
x.report(“split”) do
n.times {old_num.split(/[^\d]/).join}
end
end
Rehearsal ------------------------------------------
scan 1.080000 0.000000 1.080000 ( 1.144654)
gsub 0.380000 0.010000 0.390000 ( 0.403057)
gsub2 0.390000 0.010000 0.400000 ( 0.416074)
tr 0.290000 0.020000 0.310000 ( 0.320764)
delete 0.270000 0.010000 0.280000 ( 0.294078)
split 0.700000 0.000000 0.700000 ( 0.714139)
--------------------------------- total: 3.160000sec
user system total real
scan 1.080000 0.020000 1.100000 ( 1.101550)
gsub 0.380000 0.010000 0.390000 ( 0.404968)
gsub2 0.380000 0.010000 0.390000 ( 0.409364)
tr 0.290000 0.020000 0.310000 ( 0.318723)
delete 0.280000 0.010000 0.290000 ( 0.294650)
split 0.700000 0.000000 0.700000 ( 0.713261)
So it seems that in terms of speed, delete wins, second place for tr,
and in the fight between [^\d] and \D the first one wins by a little
(very little) margin :-).
Cheers,
Jesus.
From: Jesús Gabriel y Galán [mailto:[email protected]]
I always wanted try the benchmark stuff, and this seemed
like a good opportunity :-).
wow. thanks for the bnchmark, Jesus.
kind regards -botp
Hi –
On Tue, 25 Sep 2007, Peña, Botp wrote:
=> “5551115555”
Don’t forget \D:
old_num.gsub(/\D/, “”)
David
Peña, Botp wrote:
From: Jesús Gabriel y Galán [mailto:[email protected]]
I always wanted try the benchmark stuff, and this seemed
like a good opportunity :-).
wow. thanks for the bnchmark, Jesus.
kind regards -botp
I find my self most often reaching for gsub! or tr but hey, that helps
Thanks
TerryP.
On Sep 25, 1:31 am, “Jesús Gabriel y Galán” [email protected]
wrote:
Benchmark.bmbm do |x|
n.times {old_num.tr(“^0-9”,“”)}
gsub 0.380000 0.010000 0.390000 ( 0.403057)
tr 0.290000 0.020000 0.310000 ( 0.318723)
delete 0.280000 0.010000 0.290000 ( 0.294650)
split 0.700000 0.000000 0.700000 ( 0.713261)So it seems that in terms of speed, delete wins, second place for tr,
and in the fight between [^\d] and \D the first one wins by a little
(very little) margin :-).Cheers,
Jesus.
That’s awesome, thanks.