johnk
1
I have the following:
a = (y != 0) ? (x/y) : 0
There must be a sexier way of doing this! Any suggestions?
On a side note… how do we do exception handling on the same line as
statement?
a = x/y rescue 0
That does not work but does it make sense? Is it because dividing by
zero does not throw an exception?
Thanks for your help! 
Your Friend,
John
–
John K.
[email protected]
http://www.kopanas.com
http://www.soen.info
johnk
2
a = begin
x / y
rescue ZeroDivisionError
0
end
johnk
3
On Thu, 25 Jan 2007, John K. wrote:
That does not work but does it make sense? Is it because dividing by
zero does not throw an exception?
Thanks for your help! 
works for me?
harp:~ > ruby -e’ a = 42/0 rescue 42; p a ’
42
i think you’re doing the right thing with
a = x/y rescue 0
how doesn’t it work?
regards.
-a
johnk
4
On Jan 24, 2007, at 10:52 AM, [email protected] wrote:
harp:~ > ruby -e’ a = 42/0 rescue 42; p a ’
-a
we can deny everything, except that we have the possibility of
being better.
simply reflect on that.
If you’re not limited to Integers:
1/0
ZeroDivisionError: divided by 0
from (irb):1:in `/’
from (irb):1
1.0/0
=> Infinity
1/0.0
=> Infinity
0.0/0.0
=> NaN
If either x or y are Float, then dividing by zero isn’t an exception.
You could force an exception if you want to get back to an Integer:
(1.0/0).to_i
FloatDomainError: Infinity
from (irb):7:in to_i' from (irb):7 (0.0/0.0).to_i FloatDomainError: NaN from (irb):8:in
to_i’
from (irb):8
-Rob
Rob B. http://agileconsultingllc.com
[email protected]
johnk
5
I need to keep it as a float… that is my problemo :-(.
On 1/24/07, Rob B. [email protected] wrote:
FloatDomainError: NaN
–
John K.
[email protected]
http://www.kopanas.com
http://www.soen.info
johnk
6
On Jan 24, 2007, at 1:46 PM, John K. wrote:
There must be a sexier way of doing this! Any suggestions?
Thanks for your help! 
0.0/0.0
from (irb):7
I need to keep it as a float… that is my problemo :-(.
John K.
[email protected]
http://www.kopanas.com
http://www.cusec.net
http://www.soen.info
Perhaps…
a = x/y
a = 0.0 unless a.finite?
-Rob
Rob B. http://agileconsultingllc.com
[email protected]