Display specific field that has duplicate name to other table

HI TO ALL

I want to display a specific field in
my VIEW but they have the same FIELD name…For example, th id in the
PAYMENTS table and the id in the SUGGESTS table have the same field
name… I want to be able to display the correct PAYMENTS id and
correct SUGGESTS id…
My Database is big im having a hard time to trace…which id it belongs
to.

In my ruby on rails action or method Controller:
def print_two_table
@p = Pay.find_by_sql("SELECT p.id, p.topic, s.id, s.income, s.price FROM
pays as P LEFT OUTER JOIN suggests AS s ON s.b_id = p.b_id WHERE
p.created_at BETWEEN ‘2008-03-04’ AND ‘2008-07-06’ ")
end

In my View action or method:

<%= @p.each do |form| %>
<%= form.income %>

<%= form.id %>

<%= form.income %>

<% end %>

It gives me the wrong id i want to display…I want to display id in
payments.

On Apr 11, 8:11am, Ad Ber [email protected] wrote:

In my ruby on rails action or method Controller:
def print_two_table
@p = Pay.find_by_sql("SELECT p.id, p.topic, s.id, s.income, s.price FROM
pays as P LEFT OUTER JOIN suggests AS s ON s.b_id = p.b_id WHERE
p.created_at BETWEEN ‘2008-03-04’ AND ‘2008-07-06’ ")
end
If you’re going to do it like this (rather than using associations)
you’re going to need to alias the column names (ie select s.id as
suggest_id)

Fred

Frederick C. wrote in post #992073:

On Apr 11, 8:11am, Ad Ber [email protected] wrote:

In my ruby on rails action or method Controller:
def print_two_table
@p = Pay.find_by_sql("SELECT p.id, p.topic, s.id, s.income, s.price FROM
pays as P LEFT OUTER JOIN suggests AS s ON s.b_id = p.b_id WHERE
p.created_at BETWEEN ‘2008-03-04’ AND ‘2008-07-06’ ")
end
If you’re going to do it like this (rather than using associations)
you’re going to need to alias the column names (ie select s.id as
suggest_id)

Fred

Uhm…I have already made the necessary relationships…do you have any
idea how i can be able to display the proper id want to display?

On Apr 11, 9:54am, Ad Ber [email protected] wrote:

you’re going to need to alias the column names (ie select s.id as
suggest_id)

Fred

Uhm…I have already made the necessary relationships…do you have any
idea how i can be able to display the proper id want to display?

Well you’re not using them. if you were You’d do something like
Pay.where( …).includes(:suggests)
and then iterate over your pay objects and their associated suggest
objects.
If you don’t want to do that then like I said you need to alias the
ambiguous column names so that they aren’t ambiguous anymore.

Fred

This forum is not affiliated to the Ruby language, Ruby on Rails framework, nor any Ruby applications discussed here.

| Privacy Policy | Terms of Service | Remote Ruby Jobs