CSV to XML


#1

Great forum, been a reader for a long time. My first post comes as a
request for some help.

I am trying to process a CSV of undetermined length (want to know how to
incorporate ‘wc -l’).

The CSV has 4 columns that I want to map to XML nodes.

I am having trouble writing each CSV line to an individual XML file (100
lines = 100 XML files). The first CSV element in each line would be the
xml file name.

Seems pretty straight forward but I am pulling my hair out trying to
make it work. Any help would be greatly appreciated. I have googled
everywhere for it. I appreciate any help in advance!


#2

Thanks James, gettign this error, trying to work it out:

makeXML.rb:7: undefined method +' for nil:NilClass (NoMethodError) from /Library/Ruby/Gems/1.8/gems/fastercsv-1.4.0/lib/faster_csv.rb:1514:ineach’
from
/Library/Ruby/Gems/1.8/gems/fastercsv-1.4.0/lib/faster_csv.rb:1017:in
foreach' from /Library/Ruby/Gems/1.8/gems/fastercsv-1.4.0/lib/faster_csv.rb:1191:inopen’
from
/Library/Ruby/Gems/1.8/gems/fastercsv-1.4.0/lib/faster_csv.rb:1016:in
`foreach’
from makeXML.rb:6


#3

On Oct 25, 2008, at 1:41 PM, Bee T. wrote:

(100
lines = 100 XML files). The first CSV element in each line would be
the
xml file name.

Seems pretty straight forward but I am pulling my hair out trying to
make it work. Any help would be greatly appreciated. I have googled
everywhere for it. I appreciate any help in advance!

How about something like this:

$ cat for_xml.csv
filename
one
two
three
$ cat csv2xml.rb
#!/usr/bin/env ruby -wKU

require “rubygems”
require “faster_csv”

FCSV.foreach(ARGV.shift, :headers => true) do |row|
File.open(row[“filename”] + “.xml”, “w”) do |f|
# create XML data here…
end
end
$ ruby csv2xml.rb for_xml.csv
$ ls *.xml
one.xml three.xml two.xml

Hope that helps.

James Edward G. II