Create a counter in a hash to return first 10 results only

Ruby
1

New to ruby…

I created a hash array and everything works fine except I can’t figure
out how to include a counter to return the first 10 results only.

Thanks John

Here is the code

h = Hash.new
good_words.each { |w|
if h.has_key?(w)
h[w] = h[w] + 1
else
h[w] = 1
end
}

sort the hash by value, and then print it in this sorted order

h.sort{|a,b| b[1]<=>a[1]}.each { |elem|

puts “”#{elem[0]}" has #{elem[1]} occurrences"

}

2

John Dale wrote:

New to ruby…

I created a hash array and everything works fine except I can’t figure
out how to include a counter to return the first 10 results only.

Thanks John

Here is the code

h = Hash.new
good_words.each { |w|
if h.has_key?(w)
h[w] = h[w] + 1
else
h[w] = 1
end
}

sort the hash by value, and then print it in this sorted order

h.sort{|a,b| b[1]<=>a[1]}.each { |elem|

puts “”#{elem[0]}" has #{elem[1]} occurrences"

}

referred to an earlier post and figured this out.

Thanks

John

3

On 24.02.2010 20:52, John Dale wrote:

h = Hash.new
h.sort{|a,b| b[1]<=>a[1]}.each { |elem|

puts "\"#{elem[0]}\" has #{elem[1]} occurrences"

}

referred to an earlier post and figured this out.

Like?

h = Hash.new 0
…
h[w] += 1
…

puts h.sort_by {|w,c| -c}[0,10]

Kind regards

robert