Convert string array to interger array in in one line


#1

hi guys

i have a array like this for e.g

[[“0”, “0”, “0”, “0”, “0”, “3”, “3”],
[“0”, “0”, “0”, “0”, “0”, “3”, “3”],
[“0”, “0”, “0”, “0”, “0”, “3”, “3”],
[“0”, “3”, “0”, “0”, “0”, “0”, “3”],
[“0”, “0”, “0”, “0”, “0”, “0”, “3”]]

how wud i convert to this

[[0, 0, 0, 0, 0, 3, 3],
[0, 0, 0, 0, 0, 3, 3],
[0, 0, 0, 0, 0, 3, 3],
[0, 0, 0, 0, 0, 3, 3],
[0, 0, 0, 0, 0, 0, 3],
[0, 0, 0, 0, 0, 0, 3],
[0, 3, 0, 0, 0, 0, 3],
[0, 0, 0, 0, 0, 0, 3],

i.e a string array to integer array in 1 line if possible

pls help


#2

Alle Wednesday 05 November 2008, Jags R. ha scritto:

how wud i convert to this
i.e a string array to integer array in 1 line if possible

pls help

a.map{|i| i.map{|s| s.to_i}}

Stefano


#3

On Nov 5, 8:08 am, Jags R. removed_email_address@domain.invalid wrote:

how wud i convert to this
i.e a string array to integer array in 1 line if possible

pls help

Posted viahttp://www.ruby-forum.com/.

Maybe this is a little clearer:

aStrings = [[“0”, “0”, “0”, “0”, “0”, “3”, “3”],
[“0”, “0”, “0”, “0”, “0”, “3”, “3”],
[“0”, “0”, “0”, “0”, “0”, “3”, “3”],
[“0”, “3”, “0”, “0”, “0”, “0”, “3”],
[“0”, “0”, “0”, “0”, “0”, “0”, “3”]]

aFixnums = aStrings.map{|i| i.map{|s| s.to_i}}
puts aStrings[0][0].class.to_s # => String
puts aFixnums[0][0].class.to_s # => Fixnum
puts aFixnums[0][0].integer? # => true (So a Fixnum is_a Integer)

Note that the last line asserts that a Fixnum object is indeed an
Integer

HTH,
Richard


#4

On Wed, Nov 5, 2008 at 7:08 AM, Jags R. removed_email_address@domain.invalid wrote:

how wud i convert to this
i.e a string array to integer array in 1 line if possible
Here’s a weird one for your enjoyment (arr is your array)…

require ‘matrix’; p Matrix[*arr].map {|i| i.to_i}.to_a

…of course, just like Stefano’s solution, the object must respond to
the #to_i method.

You can #join it and split it up (#each_slice) again (my first cool
solution, but looks really ugly). Mapping twice is the easiest and
is the way you probably should go.

Todd