Convert elements of array into a single integer

Ruby
1

Hi,

I’ve tried searching for this on the forum and couldn’t find an answer.
Apologies if it’s already out there.

I’ve converted the digits of an integer into elements of an array, like
so:

x = some_integer

y = “#{x}”.scan(/./)

Now, after using y for my nefarious purposes, I would like to re-convert
the elements (still containing one digit each) into an integer.

I don’t mind writing a routine for it, but was wondering if there’s some
magical way to do it quicker :slight_smile:

Ta,

Anna

2

On Thu, Oct 11, 2012 at 8:14 PM, Anna B. [email protected] wrote:

y = “#{x}”.scan(/./)
Better

y = x.to_s.scan /./

You can also do this numerically

irb(main):008:0> x = 113453
=> 113453
irb(main):009:0> y = []
=> []
irb(main):010:0> while x > 0; x, b = x.divmod 10; y.unshift b; end
=> nil
irb(main):011:0> y
=> [1, 1, 3, 4, 5, 3]

respectively

irb(main):015:0> x = 113453
=> 113453
irb(main):016:0> y = []
=> []
irb(main):017:0> while x > 0; x, b = x.divmod 10; y.unshift b.to_s; end
=> nil
irb(main):018:0> y
=> [“1”, “1”, “3”, “4”, “5”, “3”]

or even

irb(main):030:0> x = 113453
=> 113453
irb(main):031:0> y = []
=> []
irb(main):032:0> while x > 0; y.unshift((x, b = x.divmod 10).last.to_s);
end
=> nil
irb(main):033:0> y
=> [“1”, “1”, “3”, “4”, “5”, “3”]

Now, after using y for my nefarious purposes, I would like to re-convert
the elements (still containing one digit each) into an integer.

You make me curious…

I don’t mind writing a routine for it, but was wondering if there’s some
magical way to do it quicker :slight_smile:

No magic needed

z = y.join.to_i

Kind regards

robert

3

2012/10/11 Anna B. [email protected]:

x = some_integer
y = “#{x}”.scan(/./)

Assuming y is an array like [‘1’, ‘2’, ‘3’]:

join the array into a string like “123” and convert to an integer:

x = y.join(‘’).to_i

The other way around can be done similarly:
y = x.to_s.split(‘’) # convert integer to string and split between
characters

– Matma R.

4

Thank you both!