Convert a char into numbre

I am have an String object like “12345678”, and an Array object like
[ 8,7,6,5,4,3,2,1].
The main idea is:

myStr = ‘12345678’
myArray = [8,7,6,5,4,3,2,1]
total = 0

for i in 0…7
total+= myStr[ i ].to_i * myArray[ i ]
end

The awaited result is 120 but coz myStr[ i ] returns the ascii fixnum
i can’ t get it

Like a quick solution i have to do this:

myStr = ‘12345678’
myArray = [8,7,6,5,4,3,2,1]
total = 0

for i in 0…7
total += ( String.new << myStr[ i ] ).to_i * myArray[ i ]
end

It’s so horrible!!! :frowning:

Please, help my code to be beautiful as ruby is

Roberto Decurnex Gorosito wrote:

end

The awaited result is 120 but coz myStr[ i ] returns the ascii fixnum
i can’ t get it

Try myStr[i,1]

You are right, thanks!

On Dec 18, 8:35 am, Roberto Decurnex Gorosito
[email protected] wrote:

end

The awaited result is 120 but coz myStr[ i ] returns the ascii fixnum
i can’ t get it

Fixnum#chr will give you the String back and then you can use
String#to_i:

total = 0
myArray.each_with_index do |x, i|
total += x * myStr[i].chr.to_i
end
total
=> 120

Alternately, you could just subtract 48 from myStr[i] if you’ll always
be using ASCII, but I don’t think that’s a good way to do things.

As a one-liner:
myStr.split(//).zip(myArray).inject(0) {|acc, arr| acc + arr[0].to_i *
arr[1]}
=> 120

That’s what i was looking for chr, i just forget that one. Thanks!

roberto te llego?
lo que tenes que hacer es , biceps y espalada hoy

2007/12/18, yermej [email protected]:

This forum is not affiliated to the Ruby language, Ruby on Rails framework, nor any Ruby applications discussed here.

| Privacy Policy | Terms of Service | Remote Ruby Jobs