my-ruby
1
Here I just played to see how printing statement behaves with “nil”
values. Here we go:
p nil
nil
=> nil #good as expected.
puts nil
#as nil.to_s causes the “blank” in the first line.
=> nil #good as expected.
p puts nil
#as nil.to_s causes the “blank” in the first line
nil
=> nil # good as expected, as p works here on the return value of puts.
=========================
Confusion begins with the below :
p(puts(print(“hi”)))
hi
nil
=> nil # this is the actual output.
But from the above analysis I expected the below:
p(puts(print(“hi”)))
hi
nil
=> nil
Could you explain the gap between my assumption and the actual one?
Thanks.
my-ruby
2
Print doesn’t append a newline, so the puts’d nil is tacked onto the end
of
the ‘hi’
I’d write more, but I hate typing on my phone.
Sent from my phone, so excuse the typos.
my-ruby
3
Matthew K. wrote in post #1097228:
Print doesn’t append a newline, so the puts’d nil is tacked onto the end
of
the ‘hi’
I’d write more, but I hate typing on my phone.
Sent from my phone, so excuse the typos.
Humm! perfect catch tried and tested. and you got 100 out of 100. 
p(puts(print(“hi\n”)))
hi
nil
=> nil
my-ruby
4
Confusion begins with the below :
p(puts(print(“hi”)))
hi
nil
=> nil # this is the actual output.
But from the above analysis I expected the below:
p(puts(print(“hi”)))
hi
nil
=> nil
Well there you are adding only one newline, it’s added with puts. You
can find what you want also in this way:
p print(“hi\n\n”)
my-ruby
5
Damián M. González wrote in post #1097245:
Confusion begins with the below :
Well there you are adding only one newline, it’s added with puts. You
can find what you want also in this way:
p print(“hi\n\n”)
I actually had confusion with the below:
p(puts(print(“hi”)))
hi
nil
=> nil # this is the actual output.
how it comes? to catch this i added one ‘\n’.
my-ruby
6
why do you have confusion?? didnt they already told you how the print
commands work?
in your sample:
print(“hi”) does “hi” and returns nil
puts(nil) does “\n” and returns nil
p(nil) does “nil\n” and returns nil (the object it gets)
was it that hard to get??
my-ruby
7
Hans M. wrote in post #1097261:
why do you have confusion?? didnt they already told you how the print
commands work?
in your sample:
print(“hi”) does “hi” and returns nil
puts(nil) does “\n” and returns nil
p(nil) does “nil\n” and returns nil (the object it gets)
was it that hard to get??
Nopes! friend… I am set at all. I just told him,what made me confused.
Thanks