Confusion with Enum#with_index

Ruby
1

I was playing to understand the method “Enum#with_index” with the below
code:

===================================================
irb(main):024:0> xs = [‘a’, ‘b’, ‘c’]
=> [“a”, “b”, “c”]
irb(main):025:0> xs.to_enum.with_index(2)
=> #<Enumerator: #<Enumerator: [“a”, “b”, “c”]:each>:with_index(2)>

====================================================

irb(main):014:0> to_three = Enumerator.new do |y|
irb(main):015:1* 3.times do |x|
irb(main):016:2* y<<x
irb(main):017:2> end
irb(main):018:1> end
=> #<Enumerator: #Enumerator::Generator:0x2193ca8:each>
irb(main):027:0> to_three.with_index(2)
=> #<Enumerator: #<Enumerator:
#Enumerator::Generator:0x2193ca8:each>:with_ind
ex(2)>

====================================================

Couldn’t understand the output of “to_three.with_index(2)” .

Could anyone help me?

2

Am 02.02.2013 13:27, schrieb Arup R.:

====================================================

Couldn’t understand the output of “to_three.with_index(2)” .

Could anyone help me?

“Couldn’t understand…” is not a particularly clear way to
ask a question.

What did you expect? What puzzled you?

The “output” is only the string representation of the enumerator
object that you created. But you haven’t “done” anything with it.

3

unknown wrote in post #1094896:

Am 02.02.2013 13:27, schrieb Arup R.:

====================================================

Couldn’t understand the output of “to_three.with_index(2)” .

Could anyone help me?

#Enumerator::Generator:0x2193ca8:each>
irb(main):027:0> to_three.with_index(2) <— this output is making
confused me. What it refers to? What is it holding?

4

Am 02.02.2013 16:40, schrieb Arup R.:

#Enumerator::Generator:0x2193ca8:each>
irb(main):027:0> to_three.with_index(2) <— this output is making
confused me. What it refers to? What is it holding?

??? That’s your input.