Matthew M. ha scritto:

This week we’re going to keep it simple… very simple.

## ##

# #

specifies the aspect ratio (height divided by width).

```
ruby circle.rb 7 1.4
```

This should draw a circle of radius 7 with aspect ratio of 1.4. If done

correctly, your output will actually look like a circle (assuming 1.4 is an

accurate measure of the actual aspect ratio).

Here my solution. It is available on pastie:

http://pastie.org/215379

http://pastie.org/215380 (specs)

and it is also attached below:

# Solution to Ruby Q. #166 - Circle Drawing

# Usage:

# Circle.new(5).to_s

# or:

# Circle.new(5, 2).to_s

# or:

# Circle.new(5, 2, ‘x’).to_s

# Objects of class Circle draw circles on stdout. The aspect ratio

# correction is actually made drawing an ellipse with semimajor axis

# (a) equals to the given circle radius and semiminor axis (b) equals

# to a / aspect_ratio.

# Circle class is responsible to

# * initialize a Circle object with the given radius, aspect ratio

# and drawing char

# * initialize a canvas

# * draw the circle on its internal canvas

# * convert the canvas to string for output on stdout

class Circle

# cx, cy are the coordinates of the circle’s center.

attr_reader :cx, :cy

attr_reader :radius

# w, h are width and height of the canvas

attr_reader :w, :h

# canvas is a linear array that is initially filled with spaces

attr_reader :canvas

# Initialize a Circle object passing a value for radius, aspect

# ratio and drawing character.

def initialize(radius, aspect_ratio = 1.0, char = ‘#’)

```
@radius = radius.to_i
@aspect_ratio = aspect_ratio.to_f
@char = char
fail "Error: radius must be > 0" if @radius <= 0
fail "Error: aspect ratio must be > 0" if @aspect_ratio <= 0
# a is the semimajor axis of the ellipse and is equal to the given
# radius
@a = @radius
# b is the semiminor axis of the ellipse and is calculated from a
# and the given aspect ratio
@b = (@a / @aspect_ratio).ceil
# calculate the size of the canvas
@w, @h = (@a + 1) * 2, (@b + 1) * 2
# center coordinates correspond to the size of semiaxis.
@cx, @cy = @a, @b
# initialize the canvas with spaces
@canvas = Array.new(@w * @h, ' ')
# draw ellipse on canvas
draw_ellipse(@a, @b)
```

end

# Print circle on stdout.

def to_s

result = “”

(0…@h - 1).each do |line|

result << @canvas[line * @w…line * @w + @w - 1].to_s << “\n”

end

result

end

private

# Draw the given character on canvas to the given coordinates.

def point(x, y)

@canvas[y * @w + x] = @char

end

# Translates and mirrors point (x, y) in the quadrants taking

# advantage of the simmetries in the ellipse. Thus, for a given

# point (x, y) the method plot three other points in the remaining

# quadrants.

def plot_four_points(x, y)

point(@cx + x, @cy + y)

point(@cx - x, @cy + y)

point(@cx + x, @cy - y)

point(@cx - x, @cy - y)

end

# Draw an ellipse on canvas. This method implements a Bresenham

# based algorithm by John Kennedy

# The method calculates two set of points in the first quadrant. The

# first set starts on the positive x axis and wraps in a

# counterclockwise direction until the tangent line slope is equal

# to -1. The second set starts on the positive y axis and wraps in

# a clockwise direction until the tangent line slope is equal to -1.

def draw_ellipse(a, b)

a_square = 2 * a**2**

b_square = 2 * b2

```
draw_first_set(a, b, a_square, b_square)
draw_second_set(a, b, a_square, b_square)
```

end

# The method increments y and decides when to decrement x testing

# the sign of a function. In this case, the decision function is

# (2*ellipse_error+x_change) and its value is calculated

# iteratively.

def draw_first_set(a, b, a_square, b_square)

```
x, y = a, 0
x_change, y_change = b**2 * (1 - 2 * a), a**2
stopping_x, stopping_y = b_square * a, 0
ellipse_error = 0
while(stopping_x >= stopping_y) do
plot_four_points(x, y)
y += 1
stopping_y += a_square
ellipse_error += y_change
y_change += a_square
if (2 * ellipse_error + x_change) > 0
x -= 1
stopping_x -= b_square
ellipse_error += x_change
x_change += b_square
end
end
```

end

# The method increments x and decides when to decrement y testing

# the sign of a function. In this case, the decision function is

# (2*ellipse_error+y_change) and its value is calculated

# iteratively.

def draw_second_set(a, b, a_square, b_square)

```
x, y = 0, b
x_change, y_change = b**2, a**2 * (1 - 2 * b)
stopping_x, stopping_y = 0, a_square * b
ellipse_error = 0
while stopping_x <= stopping_y do
plot_four_points(x, y)
x += 1
stopping_x += b_square
ellipse_error += x_change
x_change += b_square
if (2 * ellipse_error + y_change) > 0
y -= 1
stopping_y -= a_square
ellipse_error += y_change
y_change += a_square
end
end
```

end

end

# Usage:

# ruby circle.rb 7 #=> print out a circle of radius 7

# ruby circle.rb 7 1.8 #=> print out a circle of radius 7 and aspect

ratio 1.8

# ruby circle.rb 7 1.8 x #=> print out a circle of radius 7 and aspect

ratio 1.8

# using the ascii char ‘x’

print Circle.new(ARGV[0], ARGV[1] || 1.0, ARGV[2] || ‘#’).to_s if $0 ==

**FILE**