How do we handle null value from opened HKEY instance. if
(reg.read_i(name)!="") in below line I have tried but it doesn’t work
properly.
Ex:
Win32::Registry::HKEY_LOCAL_MACHINE.open(REG_PATH_1,Win32::Registry::Constants::KEY_ALL_ACCESS)
do |reg|
if (reg.read_i(name)!="")
return reg.read_i(name)
end
end
I need another instance to open for different REG_PATH. The reason
behind that is if the reg key is in first path then return the value
other wise open the key to read the reg key from different path.
On Thu, Jul 8, 2010 at 10:52 AM, Navaneet K. [email protected]
wrote:
end
I need another instance to open for different REG_PATH. The reason
behind that is if the reg key is in first path then return the value
other wise open the key to read the reg key from different path.
I have no idea about that API, but if read_i is returning nil for
non-existing keys, you can try this:
unless (key = reg.read_i(name)).nil?
return key
end
On Thu, Jul 8, 2010 at 10:52 AM, Navaneet K. [email protected]
wrote:
� �end
I need another instance to open for different REG_PATH. The reason
behind that is if the reg key is in first path then return the value
other wise open the key to read the reg key from different path.
I have no idea about that API, but if read_i is returning nil for
non-existing keys, you can try this:
unless (key = reg.read_i(name)).nil?
return key
end
Jesus.
Thanks for your reply.
Just clarification, The specified key is not exist not the value is
having null. I mean the ‘name’ key is not exist in that path. How do we
handle this in ruby.