if your page test.php
[email protected]_get_contents(“http://localhost/test.php”);
then error
Posted at Nginx Forum:
http://forum.nginx.org/read.php?2,5607,5607#msg-5607
if your page test.php
[email protected]_get_contents(“http://localhost/test.php”);
then error
Posted at Nginx Forum:
http://forum.nginx.org/read.php?2,5607,5607#msg-5607
nginx/0.7.61 for win
fcgi/5.3.0
Posted at Nginx Forum:
http://forum.nginx.org/read.php?2,5607,5608#msg-5608
I try not into recursion
test.php
still error
Posted at Nginx Forum:
http://forum.nginx.org/read.php?2,5607,5724#msg-5724
In the future, perhaps you should:
That way people don’t have to guess about what you are doing.
On Sun, 2009-09-06 at 23:48 -0400, afen wrote:
I try not into recursion
<? $id=$_GET['id']; if ($id==1){
test.php
if ($id==“1”){
Note that all _GET variables will be strings. You have to coerce them
if you want them to become other types.
I also seriously doubt this worked under Apache. This is a PHP
programming error. Making false claims doesn’t help get your problem
solved.
Cliff
Hello!
On Thu, Sep 03, 2009 at 11:55:47PM -0400, afen wrote:
if your page test.php
[email protected]_get_contents(“http://localhost/test.php”);
then error
Looks like infinite recursion for me.
See http://en.wikipedia.org/wiki/Recursion
Maxim D.
On Sun, 2009-09-06 at 21:52 -0700, Cliff W. wrote:
<? $id=$_GET['id']; if ($id==1){if ($id==“1”){
Note that all _GET variables will be strings. You have to coerce them
if you want them to become other types.
Bah, I forgot that PHP stupidly coerces crap without prompting.
“1” == 1 is true in PHP.
Better post your config.
Cliff
On Mon, Sep 7, 2009 at 10:48 AM, afen[email protected] wrote:
still error
it works here.
<?php $id=$_GET['id']; if ($id==1){ echo"1"; }else{ [email protected]_get_contents("http://localhost/test.php?id=1"); echo $html; } ?>returns 1 no matter what the id is.
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