In this case sounds like RSS feed URL is your natural primary key. You
could add untokenized ‘id’ field to your documents and then retrieve and
update them by using URLs as keys. And you could even have a more
natural field name if you create index with some optional params.
Example:
url = ‘Peak Obsession’
index = Ferret::Index::Index.new(:path => “#{RAILS_ROOT}/db/ferret”,
:id_field => ‘url’)
document = Ferret::Document::Document.new
document << Ferret::Document::Field.new(‘url’, url,
Ferret::Document::Field::Store::YES,
Ferret::Document::Field::Index::UNTOKENIZED)
document << Ferret::Document::Field.new(‘content’, ‘Rails are great!’,
Ferret::Document::Field::Store::YES,
Ferret::Document::Field::Index::TOKENIZED)
index << document
document = index[url]
puts document[‘url’] == url # true
document[‘content’] = ‘I agree’
index.update(url, document)
index[url][‘content’] == I agree # true
index.size == 1 # true
–
Sergei S.
Red Leaf Software LLC
web: http://redleafsoft.com
Hi All,
I have a Ferret index containing some cached RSS feeds.
I have a nightly cron script to cache the feeds, and I’d like to update
the index with the latest feeds.
I see the Index class has an update method, but I can’t work out how to
get the id of the relevant document to pass in.
Lets say I have a file called “google_news.xml”
I want to go:
my_index.update(google_id, google_doc)
I’m sure this is way too easy and I’m being massively dumb, but - - any
hints/advice gratefully received.
Many Thanks,
Steven
