Array to hash

Ruby
1
Hello all
    Is there a method to collect the items in an array into a hash
 
I want to go from this X =[1,2,3,4,5,6] to this Y={1 =>2, 3 =>4, 5 =>6}
 
Just seems like there should be one
 
Thanks in advance
 
Sam
2

Hi –

On 3/20/07, Servando G. [email protected] wrote:

Hello all
Is there a method to collect the items in an array into a hash

I want to go from this X =[1,2,3,4,5,6] to this Y={1 =>2, 3 =>4, 5 =>6}

Hash[*X]

David

3

On 3/20/07, Servando G. [email protected] wrote:

Sam
Try this

arr = [1,2,3,4,5,6]
ahash = Hash[*arr]
p arr
p ahash

Harry

–

http://www.kakueki.com/ruby/list.html
Japanese Ruby List Subjects in English

4
David
    No Way that is to easy. My new question to you is how does this work. Where can I read the source code for this method

> Hi --
>
> On 3/20/07, Servando Garcia wrote:
>
>> Hello all
>> Is there a method to collect the items in an array into a hash
>>
>> I want to go from this X =[1,2,3,4,5,6] to this Y={1 =>2, 3 =>4,
>> 5 =>6}
>>
> Hash[*X]
>
>
> David
5

On 20 mars 07, at 12:53, Servando G. wrote:

Where can I read the source code for this method ?

<http://svn.ruby-lang.org/cgi-bin/viewvc.cgi/trunk/hash.c?
revision=11708&view=markup>

The function you are looking for is ‘rb_hash_s_create’.

6

Hi –

On 3/20/07, Servando G. [email protected] wrote:

David
No Way that is to easy. My new question to you is how does this work.

The ‘unarray’ operator * turns an array into a list. So in effect
you’re doing:

Hash[1,2,3,4,5,6]

David

7
Guess I should have googled harder/longer I have found some code that appears to work. Now I'll have to spend sometime stepping through it.
Here is the code:
 
class Array
def to_h(&block)
Hash[*self.collect { |v|
[v, block.call(v)]
}.flatten]
end
end
 
 
and the link to the page:
http://snippets.dzone.com/posts/show/302
 
Harold, Please forgive my impatience
 
Sam

> Hello all
>   Is there a method to collect the items in an array into a hash
>
> I want to go from this X =[1,2,3,4,5,6] to this Y={1 =>2, 3 =>4, 5
> =>6}
>
> Just seems like there should be one
>
> Thanks in advance
>
> Sam
8

On Tue, Mar 20, 2007 at 08:33:09PM +0900, Servando G. wrote:

I want to go from this X =[1,2,3,4,5,6] to this Y={1 =>2, 3 =>4, 5 =>6}
 
Just seems like there should be one
 
Thanks in advance
 
Sam

I’m glad you got the answer you were seeking. I have a request, though:

Please provide plain text email content in the future. Some of us
(intentionally) avoid HTML email.

9

On 3/20/07, Servando G. [email protected] wrote:

David
No Way that is to easy. My new question to you is how does this work.
Where can I read the source code for this method

It’s a combination of two things:

  1. Hash.[] creates a hash from a comma separated even-length list

Hash[1,2,3,4,5,6] # => { 1=>2, 3=>4, 5=>6 }

  1. *ary converts an array into a comma-separated list

def foo(a, b=nil, c=nil)
p a
p b
p c
end

ary = [1,2,3]

def foo(a, b=nil, c=nil)
p a
p b
p c
end

ary = [1,2,3]

irb> foo(ary)
[1, 2, 3]
nil
nil
=> nil
irb> foo(*ary)
1
2
3
=> nil

martin