Alphabetizing

Ruby
1

Hi,

I’m trying to write a code where I can alphabetize the players last_name
with its batting average

players_avg= << PLAYERS
Barry Bonds, .293
Mike Gallego, .263
Ichiro Suzuki, .396
Tony Gwynn, .403
Alex R., .310
PLAYERS

players = presidents_avg.strip.collect { |players| players.strip
}.compact

#initialiating players_by_last_name with an empty array
players_by_last_name = []

2

Zenki N. wrote:

Hi,

I’m trying to write a code where I can alphabetize the players last_name
with its batting average

players_avg= << PLAYERS
Barry Bonds, .293
Mike Gallego, .263
Ichiro Suzuki, .396
Tony Gwynn, .403
Alex R., .310
PLAYERS

players = presidents_avg.strip.collect { |players| players.strip
}.compact

#initialiating players_by_last_name with an empty array
players_by_last_name = []

Try this:

players_avg = <<PLAYERS
Barry Bonds, .293
Mike Gallego, .263
Ichiro Suzuki, .396
Tony Gwynn, .403
Alex R., .310
PLAYERS

lines = players_avg.split("\n")
player_data = []

#chop lines into pieces
for line in lines
data = line.split(’,’)
names = data[0].split()
avg = data[1]
player_data << [names[0], names[1], avg]
end

#sort array by 2nd element, i.e. last name:
results = player_data.sort() do |arr1, arr2|
arr1[1]<=>arr2[1]
end

#output data:
results.each() do |arr|
puts “%s, %s %s” % [arr[1], arr[0], arr[2]]
end

–output:–
Bonds, Barry .293
Gallego, Mike .263
Gwynn, Tony .403
Rodriguez, Alex .310
Suzuki, Ichiro .396

3

On Jan 23, 2008 2:22 PM, Zenki N. [email protected] wrote:

Alex R., .310
PLAYERS

csv = CSV.parse(players_avg)
sorted = csv.sort_by{|p,a| p.split.last }
sorted.each{|p,a| puts(“%20s: %5s” % [p, a]) }

4

On Jan 22, 2008 11:22 PM, Zenki N. [email protected] wrote:

Alex R., .310
PLAYERS

players = presidents_avg.strip.collect { |players| players.strip
}.compact

#initialiating players_by_last_name with an empty array
players_by_last_name = []

This isn’t the best solution … just there for s**ts and giggles…

irb(main):002:0> players = players_avg.split(“\n”).sort_by {|i|
(i.scan /\w*/)[2]}

Todd

5

On Jan 23, 2:56 pm, Zenki N. [email protected] wrote:

retired_players = <<PLAYERS
Mike Anthony Gallego, 1985-1997
Calvin Edwin Ripken, Jr., 1981-2001
Tony K. Gwynn, 1982-2004
Dennis Eckersley, 1975-1998
PLAYERS

retired_players = <<PLAYERS
Mike Anthony Gallego, 1985-1997
Calvin Edwin Ripken, Jr., 1981-2001
Tony K. Gwynn, 1982-2004
Dennis Eckersley, 1975-1998
PLAYERS

Break it into lines

players = retired_players.scan( /^.+/ )

Turn each line into a real Player

Player = Struct.new( :name, :start_year, :end_year )
players.map!{ |line|
_, *pieces = line.match( /^(.+), (\d+)-(\d+)/ ).to_a
Player.new( *pieces )
}

Sort as you see fit

players = players.sort_by{ |player|

find the last name to use as the sort key

player.name[ /\w+(?:, (?:jr.|sr.|phd|dds))?$/i ]
}

puts players
#=> #<struct Player name=“Dennis Eckersley”, start_year=“1975”,
end_year=“1998”>
#=> #<struct Player name=“Mike Anthony Gallego”, start_year=“1985”,
end_year=“1997”>
#=> #<struct Player name=“Tony K. Gwynn”, start_year=“1982”,
end_year=“2004”>
#=> #<struct Player name=“Calvin Edwin Ripken, Jr.”,
start_year=“1981”, end_year=“2001”>

6

Slightly simpler than my previous:

retired_players = <<PLAYERS
Mike Anthony Gallego, 1985-1997
Calvin Edwin Ripken, Jr., 1981-2001
Tony K. Gwynn, 1982-2004
Dennis Eckersley, 1975-1998
PLAYERS

Find player info: yields an array of arrays

players = retired_players.scan( /^(.+), (\d+)-(\d+)/ )

players = players.sort_by{ |name, start_year, end_year|

find the last name to use as the sort key

name[ /\w+(?:, (?:jr.|sr.|phd|dds))?$/i ]
}

p players
#=> [[“Dennis Eckersley”, “1975”, “1998”], [“Mike Anthony Gallego”,
“1985”, “1997”], [“Tony K. Gwynn”, “1982”, “2004”], [“Calvin Edwin
Ripken, Jr.”, “1981”, “2001”]]

7

Thanks All for helping me out on this…

Now…here’s another issue…Say i want to display the retired players
last name in alphabetical order with its contents. Noticed this time
some has middle names, initials.

How would I tackle this?

Sorry, I’ve looked thru many books and have a difficult time solving
this…

retired_players = <<PLAYERS
Mike Anthony Gallego, 1985-1997
Calvin Edwin Ripken, Jr., 1981-2001
Tony K. Gwynn, 1982-2004
Dennis Eckersley, 1975-1998
PLAYERS

Thanks,

8

Zenki N. wrote:

Find player info: yields an array of arrays

Ripken, Jr.", “1981”, “2001”]]

Thanks. Is there a way where I can display the full tenure? ie.
“1975-1998” instead?

I want to display in full:

‘Dennis Eckersley, 1975-1998’

Replace:

p players

with:

players.each { |p, s, e|
puts “#{p}, #{s}-#{e}”
}

9

Gavin K. wrote:

Slightly simpler than my previous:

retired_players = <<PLAYERS
Mike Anthony Gallego, 1985-1997
Calvin Edwin Ripken, Jr., 1981-2001
Tony K. Gwynn, 1982-2004
Dennis Eckersley, 1975-1998
PLAYERS

Find player info: yields an array of arrays

players = retired_players.scan( /^(.+), (\d+)-(\d+)/ )

players = players.sort_by{ |name, start_year, end_year|

find the last name to use as the sort key

name[ /\w+(?:, (?:jr.|sr.|phd|dds))?$/i ]
}

p players
#=> [[“Dennis Eckersley”, “1975”, “1998”], [“Mike Anthony Gallego”,
“1985”, “1997”], [“Tony K. Gwynn”, “1982”, “2004”], [“Calvin Edwin
Ripken, Jr.”, “1981”, “2001”]]

Thanks. Is there a way where I can display the full tenure? ie.
“1975-1998” instead?

I want to display in full:

‘Dennis Eckersley, 1975-1998’

10

Zenki N. wrote:

Thanks All for helping me out on this…

Now…here’s another issue…Say i want to display the retired players
last name in alphabetical order with its contents. Noticed this time
some has middle names, initials.

How would I tackle this?

Sorry, I’ve looked thru many books and have a difficult time solving
this…

retired_players = <<PLAYERS
Mike Anthony Gallego, 1985-1997
Calvin Edwin Ripken, Jr., 1981-2001
Tony K. Gwynn, 1982-2004
Dennis Eckersley, 1975-1998
PLAYERS

Thanks,

My attempt:

retired_players = <<PLAYERS
Mike Anthony Gallego, 1985-1997
Calvin Edwin Ripken, Jr., 1981-2001
Tony K. Gwynn, 1982-2004
Dennis Eckersley, 1975-1998
PLAYERS

#A container for each player’s data:
Player = Struct.new(:last, :first_middle, :years)

#An array to hold each Player:
players = []

#Divide the string into lines:
lines = retired_players.split("\n")
lines.each do |line|
pieces = line.split(’,’)

#Extract the years played:
years = pieces[-1].strip()

#Extract the title, e.g. .jr, .sr
if pieces.length == 3 #then player has a title like .jr, .sr
title = pieces[1].strip()
else
title = false
end

#Extract the names:
names = pieces[0].split()
last = names[-1]
first_middle = names[0…-2].join(" “)
if title
last = sprintf(”%s %s", last, title)
end

#Create a new Player with the above data:
players << Player.new(last, first_middle, years)
end

#Sort the Player objects in the players array by last name:
sorted_players = players.sort do |p1, p2|
p1.last<=>p2.last
end

#Output the sorted players:
sorted_players.each do |player|
puts sprintf("%s, %s %s", player.last, player.first_middle,
player.years)
end

–output:–
Eckersley, Dennis 1975-1998
Gallego, Mike Anthony 1985-1997
Gwynn, Tony K. 1982-2004
Ripken Jr., Calvin Edwin 1981-2001

11

On Jan 23, 2008 7:36 PM, 7stud – [email protected] wrote:

Zenki N. wrote:

Thanks All for helping me out on this…

Now…here’s another issue…Say i want to display the retired players
last name in alphabetical order with its contents. Noticed this time
some has middle names, initials.

My golf attempt. Please don’t use this for production code…

players_avg = <<PLAYERS
Mike Anthony Gallego, 1985-1997
Calvin Edwin Ripken, Jr., 1981-2001
Tony K. Gwynn, 1982-2004
Dennis Eckersley, 1975-1998
PLAYERS

puts players = players_avg.split(“\n”).sort_by {|i| i.scan /\w*?,/}

Todd

12

On Jan 23, 2008 3:56 PM, Zenki N. [email protected] wrote:

retired_players = <<PLAYERS
Mike Anthony Gallego, 1985-1997
Calvin Edwin Ripken, Jr., 1981-2001
Tony K. Gwynn, 1982-2004
Dennis Eckersley, 1975-1998
PLAYERS

Thanks,

If you cannot identify the last name by position – I don’t know –
then maybe you need to use a database. I suppose you can grab the
first written word before a comma, but I’m not sure I’d trust that.

Todd