# A simple analogue question

Hi everyone.

If I have two signals entering a receiver, both with a power of 0 dBm,
what would be the total input power seen by the receiver? Is it 3 dBm
or 6 dBm?

Thanks.

Sebastiaan

Sebastiaan H.
Tel: +27 72 950 9370

On Sun, Apr 11, 2010 at 10:12 AM, Sebastiaan H. [email protected]
wrote:

Hi everyone.

If I have two signals entering a receiver, both with a power of 0 dBm,
what would be the total input power seen by the receiver? Is it 3 dBm
or 6 dBm?

Bringing it back to power instead of ratios helps clear this up. Both
transmitters are emitting 1mW, for a total input power of 2mW.

Calculating dBm on that yields:

10*log10(2mW/1mW) = 3dBm

Hope this helps!

Thanks.

Sebastiaan

Brian

If I have two signals entering a receiver, both with a power of 0 dBm,
what would be the total input power seen by the receiver? Is it 3 dBm
or 6 dBm?

Anywhere between 6dBm and -174 + 10*log() dBm,
assuming a 50-Ohm system at room temperature.

## JD ‘correlation’ B.

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