Hi everyone.
I was wondering if someone could please answer the following question?
If I have two signals entering a receiver, both with a power of 0 dBm,
what would be the total input power seen by the receiver? Is it 3 dBm
or 6 dBm?
Thanks.
Sebastiaan
–
Sebastiaan H.
Tel: +27 72 950 9370
On Sun, Apr 11, 2010 at 10:12 AM, Sebastiaan H. [email protected]
wrote:
Hi everyone.
I was wondering if someone could please answer the following question?
If I have two signals entering a receiver, both with a power of 0 dBm,
what would be the total input power seen by the receiver? Is it 3 dBm
or 6 dBm?
Bringing it back to power instead of ratios helps clear this up. Both
transmitters are emitting 1mW, for a total input power of 2mW.
Calculating dBm on that yields:
10*log10(2mW/1mW) = 3dBm
Hope this helps!
Thanks.
Sebastiaan
Brian
If I have two signals entering a receiver, both with a power of 0 dBm,
what would be the total input power seen by the receiver? Is it 3 dBm
or 6 dBm?
Anywhere between 6dBm and -174 + 10*log() dBm,
assuming a 50-Ohm system at room temperature.
JD ‘correlation’ B.
LART. 250 MIPS under one Watt. Free hardware design files.
http://www.lartmaker.nl/