if i have
my_list = “2-131-25-5558-247-68”
and I want to get rid of the last element…
I wrote :
my_list.split(’-’) - my_list.split(’-’).last.to_a =>
“22-13-25-58-47”
which runs well… but isn’t too complex… ?
tfyl
joss
On Feb 20, 2007, at 7:20 AM, Josselin wrote:
if i have
my_list = “2-131-25-5558-247-68”
and I want to get rid of the last element…
I would use a regular expression:
my_list = “2-131-25-5558-247-68”
=> “2-131-25-5558-247-68”my_list.sub(/-\d+\Z/, “”)
=> “2-131-25-5558-247”
Hope that helps.
James Edward G. II
Josselin wrote:
if i have
my_list = “2-131-25-5558-247-68”
and I want to get rid of the last element…
I wrote :my_list.split(’-’) - my_list.split(’-’).last.to_a =>
“22-13-25-58-47”which runs well… but isn’t too complex… ?
tfyl
joss
i’m a newb, and i am probably totally wrong, but the only way to learn
is to test what you think …
won’t the .pop method work? or does that only get rid of the last thing
entered?
Josselin schrieb:
which runs well… but isn’t too complex… ?
tfyl
joss
irb(main):001:0> my_list = “2-131-25-5558-247-68”
=> “2-131-25-5558-247-68”
irb(main):002:0> my_list.split(’-’) - my_list.split(’-’).last.to_a
=> [“2”, “131”, “25”, “5558”, “247”]
irb(main):003:0> my_list.split(’-’)[0…-1].join(’-’)
=> “2-131-25-5558-247-68”
irb(main):004:0> my_list.split(’-’)[0…-2].join(’-’)
=> “2-131-25-5558-247”
irb(main):005:0> my_list.split(’-’)[0…-3].join(’-’)
=> “2-131-25-5558”
irb(main):006:0> my_list.sub(/(?:-\d+)$/, ‘’)
=> “2-131-25-5558-247”
irb(main):007:0> my_list.sub(/(?:-\d+){2}$/, ‘’)
=> “2-131-25-5558”
irb(main):008:0> my_list.sub(/(?:-\d+){3}$/, ‘’)
=> “2-131-25”
Some ideas…
Wolfgang Nádasi-Donner
On Tue, 20 Feb 2007 14:20:07 +0100, Josselin [email protected]
wrote:
my_list = “2-131-25-5558-247-68”
D:\UserPrfs\VALLNERD>irb
irb(main):001:0> “2-131-25-5558-247-68”.split(‘-’)[0…-1].join(‘-’)
=> “2-131-25-5558-247”
Reads for me a little better than the RE version.
David V.
Array#pop will remove the last element from the original stringified
list,
which might or might not be what you want - the methods in the other
posts
only result in a new string with the last element removed.Also, #pop will return the popped value, not the original array, which
prevents you from making a single-method-chain-oneliner, a popular
Rubyist
sportDavid V.
Ah, okay. Well at least i was not COMPLETELY off. 
Derek
On Feb 20, 2:20 pm, Josselin [email protected] wrote:
if i have
my_list = “2-131-25-5558-247-68”
and I want to get rid of the last element…
If you want to keep your list as a string:
my_list.sub(/-\d+$/, ‘’)
or if you want your list as an array:
my_array = my_list.split(/-/)
my_array.delete_at(-1)
Cheers,
Nico
On Tue, 20 Feb 2007 14:33:57 +0100, Derek T.
[email protected] wrote:
won’t the .pop method work? or does that only get rid of the last thing
entered?
Array#pop will remove the last element from the original stringified
list,
which might or might not be what you want - the methods in the other
posts
only result in a new string with the last element removed.
Also, #pop will return the popped value, not the original array, which
prevents you from making a single-method-chain-oneliner, a popular
Rubyist
sport 
David V.