Exception Handling/Divide By Zero/NaN Done on One Line

I have the following:

a = (y != 0) ? (x/y) : 0

There must be a sexier way of doing this! Any suggestions?

On a side note… how do we do exception handling on the same line as
statement?

a = x/y rescue 0

That does not work but does it make sense? Is it because dividing by
zero does not throw an exception?

Thanks for your help! :slight_smile:

Your Friend,

John


John K.
[email protected]

http://www.kopanas.com

http://www.soen.info

a = begin
x / y
rescue ZeroDivisionError
0
end

On Thu, 25 Jan 2007, John K. wrote:

That does not work but does it make sense? Is it because dividing by
zero does not throw an exception?

Thanks for your help! :slight_smile:

works for me?

harp:~ > ruby -e’ a = 42/0 rescue 42; p a ’
42

i think you’re doing the right thing with

a = x/y rescue 0

how doesn’t it work?

regards.

-a

On Jan 24, 2007, at 10:52 AM, [email protected] wrote:

harp:~ > ruby -e’ a = 42/0 rescue 42; p a ’
-a

we can deny everything, except that we have the possibility of
being better.
simply reflect on that.

  • the dalai lama

If you’re not limited to Integers:

1/0
ZeroDivisionError: divided by 0
from (irb):1:in `/’
from (irb):1
1.0/0
=> Infinity
1/0.0
=> Infinity
0.0/0.0
=> NaN

If either x or y are Float, then dividing by zero isn’t an exception.

You could force an exception if you want to get back to an Integer:

(1.0/0).to_i
FloatDomainError: Infinity
from (irb):7:in to_i' from (irb):7 (0.0/0.0).to_i FloatDomainError: NaN from (irb):8:in to_i’
from (irb):8

-Rob

Rob B. http://agileconsultingllc.com
[email protected]

I need to keep it as a float… that is my problemo :-(.

On 1/24/07, Rob B. [email protected] wrote:

FloatDomainError: NaN


John K.
[email protected]

http://www.kopanas.com

http://www.soen.info

On Jan 24, 2007, at 1:46 PM, John K. wrote:

There must be a sexier way of doing this! Any suggestions?
Thanks for your help! :slight_smile:

0.0/0.0
from (irb):7

I need to keep it as a float… that is my problemo :-(.

John K.
[email protected]

http://www.kopanas.com
http://www.cusec.net
http://www.soen.info

Perhaps…

a = x/y

a = 0.0 unless a.finite?

-Rob

Rob B. http://agileconsultingllc.com
[email protected]