Problems with rb_struct_define and 64 bit Ruby

Hi all,

Ruby 1.8.4, 64 bit, built with --enable-pthread - no other special
options
Suse Linux 9.3

It’s late and I’m tired, so maybe I’m doing something dumb here, but
this
code segfaults:

/* foo.c */
#include “ruby.h”
VALUE v_my_struct;

void Init_foo(){
v_my_struct =
rb_struct_define(“MyStruct”, “fee”, “fi”, “fo”, “alpha”, “beta”,
“gamma”, 0);
}

extconf.rb

require ‘mkmf’
create_makefile(‘foo’)

test.rb

$:.unshift Dir.pwd
require ‘foo’

Take away any one member, and it works. Any more than five and it
segfaults. What gives?

Thanks,

Dan

“D” == Daniel B. [email protected] writes:

D> rb_struct_define(“MyStruct”, “fee”, “fi”, “fo”, “alpha”,
“beta”,
D> “gamma”, 0);

^^^^^^^^^^

“gamma”, NULL);

D> }

Guy Decoux

On 6/8/06, ts [email protected] wrote:

“D” == Daniel B. [email protected] writes:
D> rb_struct_define(“MyStruct”, “fee”, “fi”, “fo”, “alpha”, “beta”,
D> “gamma”, 0);

^^^^^^^^^^

“gamma”, NULL);

D> }

Gah. That’s one of the things that I absolutely despise about C as
opposed to C++. I like that I can use 0 as if it were the same thing
as NULL and not (void*)0.

-austin

“A” == Austin Z. [email protected] writes:

A> Gah. That’s one of the things that I absolutely despise about C as
A> opposed to C++. I like that I can use 0 as if it were the same
thing
A> as NULL and not (void*)0.

Well, the architecture x86_64 was created to make in sort that C
programmer understand the difference between (int)0 and (void *)0

:slight_smile:

Guy Decoux