Sorry, after reading your post again I guess I haven’t
understand your problem.
Standard Hashes are not sorted, never. If you call
sort on a Hash you get nested arrays.
[[“a”, 10], [“b”, 30], [“c”, 20]]
if you want to iterate over this array just use each.
c.each{|k, v| do_something(k, v)}
if you want the value corresponding to a key use assoc.
c.assoc(‘b’) #=> 30
(but this is slow on large arrays)
Hth
Simon