i have a table called Products whit a model product, but in the view i need show the category od the product, but whitout a model of categories...
on 2006-04-21 18:13
on 2006-04-21 18:33
X-1101 wrote: > i have a table called Products whit a model product, but in the view i > need show the category od the product, but whitout a model of > categories... The simple answer is you don't. You should have a model for each table of your database you plan on getting data from in your app (except for has_and_belongs_to_many join tables). Your model doesn't have to have any code in it, it just has to be there. then you can class Product < ActiveRecord::Base belongs_to :category end Product.find(1).category.title There is a way to do it without a model, but you would have to execute raw SQL with Product.find_by_sql(some_sql) or a similar method. I'm not familiar with this so I can't help you to much, but this seems like a far messier solution than simply creating a model.
on 2006-04-21 18:45
How are your categories modelled? The rails way to do it would be to have a separate table for categories and a corresponding model. Then you could just add associations to the two models. When you needed a list of categories (without products) you'd just do it through the model. There is a way to use ActiveRecord's connection to access the database directly through SQL and get a recordset. The real question is, why would you need to do something like that? Unless you have a very specific requirement that is unsupported by ActiveRecord, you should try and make use of the framework Rails provides to get it done more easily. After all, there is a reason why you don't see many examples of direct database access in Rails code.
on 2006-04-21 18:59
thanks Alex i have a doubt, and i don understand i have a table products and i use the scaffold command "generate scaffold product admin", and it generate the controller, models and views i navigate in the browser and i can add, update, delete and list the products my questions is if i make a copy of the list.rhtml file and a call it like list2.rhtml and i write in the browser "http://localhost:3000/admin/lista" apper the next error list You have a nil object when you didn't expect it! You might have expected an instance of Array. The error occured while evaluating nil.each
on 2006-04-21 19:04
X-1101 wrote the following on 21.04.2006 18:13 : >i have a table called Products whit a model product, but in the view i >need show the category od the product, but whitout a model of >categories... > > > You shouldn't need to. If you have a categories table, simply create the Category model. In your controler, put the product you want to use in a @product instance variable and you can call @product.category.name (or whatever attribute you need) in your view. If you don't have a category table but a category field with a "value" -> "category_name" association somewhere in your code (probably in a Hash), simply use this association to code a Product.category_name method : def category_name CATEGORY_NAMES[category] end If you really want to do raw SQL I just had to do something not so different while coding a 'VACUUM ANALYZE' as part of a cleanup procedure. You can execute raw SQL using whatever existing model linked to a table on the same database by doing : Model.connection.execute('raw sql'). But I repeat: you really don't want to access your tables directly in your views, use ActiveRecord or put a method in the Product model... Lionel.
on 2006-04-21 19:07
X-1101 wrote: > thanks Alex > > > i have a doubt, and i don understand > > > i have a table products > > and i use the scaffold command "generate scaffold product admin", and it > generate the controller, models and views > > > i navigate in the browser and i can add, update, delete and list the > products > > my questions is > > if i make a copy of the list.rhtml file and a call it like list2.rhtml > > and i write in the browser "http://localhost:3000/admin/lista" > > apper the next error list > > You have a nil object when you didn't expect it! > You might have expected an instance of Array. > The error occured while evaluating nil.each Thats because there is no controller action for "lista". Rails renders "lista.rhtml" but does not fill the proper variable before hand. when go access "list" the list action of the controller gets invoked which primarily does @products = Product.find(:all) If the controller never executes the above line, then @products is nil. So when the view does: <% @products.each do |product| %> #Same as "for product in @products" You get an error since @products is nil, and nil does nto have an "each" method.
on 2006-04-21 19:38
You can also add a :select=>"category" to a find, and it will only fill in the 'category' attribute in the returned data. It shouldn't be too hard to turn that into an array. On Friday, April 21, 2006, at 7:01 PM, Lionel Bouton wrote: >Category model. In your controler, put the product you want to use in a >If you really want to do raw SQL I just had to do something not so >Rails mailing list >Rails@lists.rubyonrails.org >http://lists.rubyonrails.org/mailman/listinfo/rails _Kevin