Hi, I have to sort a list using a number of criterions (a,b,c,d) where d is the least important criterion and a is the most important one. All comparisons should be 'higher number: better position'. This is what I have tried: -------------------------------------------------- require 'pp' h= {"Team A"=>{:a=>3, :b=>2, :c=>6, :d=>114 }, "Team B"=>{:a=>0, :b=>-2, :c=>4, :d=>112 }, "Team C"=>{:a=>3, :b=>4, :c=>4, :d=>110 }, "Team D"=>{:a=>3, :b=>4, :c=>4, :d=>108 }, } tmp=h.to_a [:d,:c,:b,:a].each do |criterion| tmp=tmp.sort_by { |a| a[1][criterion] }.reverse end pp tmp -------------------------------------------------- [["Team D", {:d=>108, :a=>3, :b=>4, :c=>4}], ["Team C", {:d=>110, :a=>3, :b=>4, :c=>4}], ["Team A", {:d=>114, :a=>3, :b=>2, :c=>6}], ["Team B", {:d=>112, :a=>0, :b=>-2, :c=>4}]] but as far as I can see 'Team C' should be better than 'Team D', because of criterion d. Is it possible that sort_by is not stable? Or is there something I did wrong? Patrick

on 2005-12-13 12:13

on 2005-12-13 12:36

Patrick Gundlach wrote: > Hi, > > I have to sort a list using a number of criterions (a,b,c,d) where d > is the least important criterion and a is the most important one. All > comparisons should be 'higher number: better position'. This is what I > have tried: > > -------------------------------------------------- > require 'pp' > > h= {"Team A"=>{:a=>3, :b=>2, :c=>6, :d=>114 }, > "Team B"=>{:a=>0, :b=>-2, :c=>4, :d=>112 }, > "Team C"=>{:a=>3, :b=>4, :c=>4, :d=>110 }, > "Team D"=>{:a=>3, :b=>4, :c=>4, :d=>108 }, > } > > tmp=h.to_a > > [:d,:c,:b,:a].each do |criterion| > tmp=tmp.sort_by { |a| a[1][criterion] }.reverse > end > > pp tmp > > -------------------------------------------------- > > [["Team D", {:d=>108, :a=>3, :b=>4, :c=>4}], > ["Team C", {:d=>110, :a=>3, :b=>4, :c=>4}], > ["Team A", {:d=>114, :a=>3, :b=>2, :c=>6}], > ["Team B", {:d=>112, :a=>0, :b=>-2, :c=>4}]] > > > but as far as I can see 'Team C' should be better than 'Team D', > because of criterion d. Is it possible that sort_by is not stable? Or > is there something I did wrong? Wouldn't this be simpler ? : h.sort_by {|k,v| [v[:a],v[:b],v[:c],v[:d]]}.reverse Best Regards, Fred

on 2005-12-13 13:09

Or using Array instead of Hash: I don't think sort is stable. You have to specify the sorting criteria, and sort only once. require 'test/unit' class TestSortBy < Test::Unit::TestCase def test_all a= [["A", 3, 2, 6, 114], ["B", 0,-2, 4, 112], ["C", 3, 4, 4, 110], ["D", 3, 4, 4, 108]] assert_equal [["A", 3, 2, 6, 114], ["C", 3, 4, 4, 110], ["D", 3, 4, 4, 108], ["B", 0, -2, 4, 112]], a.sort_by {|name,x,y,z,w| [x, w] }.reverse end end Christer

on 2005-12-13 13:10

A follow-up: > -------------------------------------------------- > require 'pp' > > h= {"Team A"=>{:a=>3, :b=>2, :c=>6, :d=>114 }, > "Team B"=>{:a=>0, :b=>-2, :c=>4, :d=>112 }, > "Team C"=>{:a=>3, :b=>4, :c=>4, :d=>110 }, > "Team D"=>{:a=>3, :b=>4, :c=>4, :d=>108 }, > } this seems to be stable: pp h.sort{ |a,b| res = a[1][:a] <=> b[1][:a] if res == 0 res = a[1][:b] <=> b[1][:b] end if res == 0 res = a[1][:c] <=> b[1][:c] end if res == 0 res = a[1][:d] <=> b[1][:d] end res }.reverse But I still would like to know if sort_by is unstable (or if am I doing something wrong). Patrick

on 2005-12-13 14:10

[...] > Wouldn't this be simpler ? : > > h.sort_by {|k,v| [v[:a],v[:b],v[:c],v[:d]]}.reverse Oh, yes, that's so much nicer. Thanks. Patrick

on 2005-12-13 14:25

Hi -- On Tue, 13 Dec 2005, Frederick Ros wrote: > Wouldn't this be simpler ? : > > h.sort_by {|k,v| [v[:a],v[:b],v[:c],v[:d]]}.reverse Or: h.sort_by {|k,v| v.values_at(:a,:b,:c,:d) }.reverse (Possibly a little clearer visually.) David -- David A. Black dblack@wobblini.net "Ruby for Rails", forthcoming from Manning Publications, April 2006!

on 2005-12-13 14:38

unknown wrote: >> h.sort_by {|k,v| [v[:a],v[:b],v[:c],v[:d]]}.reverse > > Or: > > h.sort_by {|k,v| v.values_at(:a,:b,:c,:d) }.reverse > > (Possibly a little clearer visually.) Yeah ! This one rocks !

on 2005-12-13 15:10

>> h.sort_by {|k,v| v.values_at(:a,:b,:c,:d) }.reverse >> >> (Possibly a little clearer visually.) > > > Yeah ! This one rocks ! Right, and it passes all my unittests :). So beautiful! Patrick

on 2005-12-13 15:49

Does the principle of 'least surprise' suggest that the default sort_by algorithm should be modified to be stable? It seems to me that a 'stable' algorithm is the expected behavior.

on 2005-12-13 15:56

```
Frederick Ros wrote:
> h.sort_by {|k,v| [v[:a],v[:b],v[:c],v[:d]]}.reverse
OK, this or something like it should be in the rdoc for sort_by. I was
doing something similar and wound up writing a similar sort with
multiple if tests like the OP because I didn't remember that Array
implements a sane <=>.
Also, would there be a similar cool way to do this in one step where you
want a mix of ascending and descending sorts on different parts? Say I
had a hash (in YAML):
Bobby:
age: 11
lastname: Smith
Suzy:
age: 13
lastname: Jones
Ted:
age 12
lastname: Smith
And I wanted to sort
- alphabetically by lastname
- then age oldest to youngest
So in Perl I'd do something like:
my @sorted_keys = sort { $a->{lastname} cmp $b->{lastname}
|| $b->{age} <=> $a->{age} }
keys %data;
In this case I could use
sorted_keys = data.sort_by { |k,v| [ v["lastname"], -1*v["age"] ] }
But what if I wanted reverse alphabetically by lastname (Z-A)? In perl
I'd swap $a and $b in the first comparison, but I can't think of a
spiffy way to do the same using sort_by.
```

on 2005-12-14 18:21

Patrick Gundlach <clr10.10.randomuser@spamgourmet.com> writes: > end > res > }.reverse Checkout Numeric#nonzero?.

on 2005-12-14 19:58

Mike Fletcher <lemurific+rforum@gmail.com> wrote: > > In this case I could use > > sorted_keys = data.sort_by { |k,v| [ v["lastname"], -1*v["age"] ] } > > But what if I wanted reverse alphabetically by lastname (Z-A)? In perl > I'd swap $a and $b in the first comparison, but I can't think of a > spiffy way to do the same using sort_by. class Reverser attr_accessor :obj def initialize(obj) @obj = obj end def <=>(other) other.obj <=> self.obj end end class Object def rev Reverser.new(self) end end require 'yaml' data = YAML.load %{ Bobby: age: 11 lastname: Smith Suzy: age: 13 lastname: Jones Ted: age: 12 lastname: Smith } p data sorted_keys_0 = data.sort_by {|k,v| [v["lastname"].rev, v["age"]]} sorted_keys_1 = data.sort_by {|k,v| [v["lastname"], v["age"].rev]} p sorted_keys_0 p sorted_keys_1 martin

on 2005-12-14 20:13

>> end >> res >> }.reverse > > Checkout Numeric#nonzero?. .... learning a new thing everyday... thanks. Patrick