The basic idea behind this is to have 3 arrays. the first one is the original unsorted array. the second one will be the final sorted array and the third one will be kind of a compliment. a comparison of the first object (in this case words/letters) will be done with all of the other objects and if it is the "smallest" object, it will be pushed into the sorted array. if it is compared with an object and it is "bigger" than that object, it is pushed into the compliment array. when an object is pushed into the sorted array, the original unsorted array will become empty and the compliment array will be equated to the unsorted array and this repeats itself until all the objects have been dealt with. I'll paste the code but I'm having issues because I get a bizarre sorted array. Please tell me what's wrong or what I can do to fix it. I do not want to use the bubble sort though. --------------------------------------------------------------- >#original unsorted array array = ['a','b','c','d'] >#final sorted array sortedarray =  >#compliment array unsortedarray =  >#placeholder for length comparison placeholder = array x=0 y=1 >#this while block makes sure that the length of the sorted >#array is equal to the length of the original array while sortedarray.length != placeholder.length > #this while block makes sure that every element is > #compared, and no object is the 'smallest' twice. while y != array.length if array[x] < array[y] unsortedarray.push array[y] y=y+1 else unsortedarray.push array[x] x=y y=y+1 end end >#erase the original array and replace it with the new unsorted array sortedarray.push array[x] array =  array.push unsortedarray[0..unsortedarray.length] y=1 x=0 end puts sortedarray --------------------------------------------------------------- when this program runs, I expected the same original array to be printed, then I'll go ahead to test it with mixed arrangements... but it didn't turn out well... what did I do wrong or what should I try?
on 2012-03-17 08:29
on 2012-03-17 11:53
Hi, There are two errors in your code. First, the line array.push unsortedarray[0..unsortedarray.length] does not what you expect. It does not append the elements of "unsortedarray" to "array" but rather "unsortedarray" itself. So after the first run of the inner while loop you end up with array == [['a', 'b', 'c', 'd']]. And this will break your algorithm. Since you want the *elements* appended, you have to unpack "unsortedarray" first: array.push *unsortedarray However, this is a very complicated and inefficient solution in the first place. Why not simply make "array" a reference to "unsortedarray"? array = unsortedarray Arrays are no physical objects, you don't have to actually empty and refill them. Simply overwrite the reference. The second error is that you forgot to reset "unsortedarray": unsortedarray =  I thinks that's all. However, you should replace the placeholder with the actual length of the original array. Imagine "array" as having many billions of entries. It would be insane to store the whole array in memory just for its length. And you should replace array[x] < array[y] with array[x] <= array[y]. This will make the algorithm stable (entries with the same search key will remain in their original order). Your code is actually similar to Selection Sort. I assume you're doing this as an exercise? Because if you really want to sort arrays, you should always use the built-in algorithms. Those are much faster and much more reliable than any self designed algorithm.
on 2012-03-17 16:25
Thanks for the explanations. very extensive and I appreciate and acknowledge your effort, I learned something new :). Indeed it is an exercise, I'm supposed to create a sorting program and there's a suggested algorithm which I don't seem to get my head around but since they want the array sorted, I came up with this.
on 2012-03-18 13:51
Jan E. wrote in post #1051969: > array.push unsortedarray[0..unsortedarray.length] > > does not what you expect. It does not append the elements of > "unsortedarray" to "array" but rather "unsortedarray" itself. So after > the first run of the inner while loop you end up with array == [['a', > 'b', 'c', 'd']]. And this will break your algorithm. > > Since you want the *elements* appended, you have to unpack > "unsortedarray" first: > > array.push *unsortedarray Another variant to achieve this without unpacking uses Array#concat: array.concat unsortedarray Kind regards robert