Define_method with block_given?

Ruby
1

for some reason, I want to change following code:

class A
def method_name(*args)
if block_given?
# do something with the block
yield(*args)
:block_is_given
else
# do other stuff
:block_not_given
end
end
end

to this code:

class A
%w(a b c d).each do |method_name|
define_method(method_name) do |*args|
if block_given?
# do something with the block
yield(*args)
:block_is_given
else
# do other stuff
:block_not_given
end
end
end
end

But, I get this,

A.new.a #=> :block_not_given
A.new.a { “Hello World” } #=> :block_not_given

did I miss something?
How do I can get

A.new.a { “Hello World” }

to produce #=> :block_is_given and executes the block?

2

On Sun, Jan 22, 2012 at 12:38 AM, Adit Cahya Ramadhan Adit <
[email protected]> wrote:

 :block_not_given
   # do something with the block

But, I get this,

–
Posted via http://www.ruby-forum.com/.

block_given? gets confused about what context it should be looking in.
To
get around it, just explicitly accept a block.

class A
%w(a b c d).each do |method_name|
define_method(method_name) do |*args, &block|
if block
# do something with the block
block.call(*args)
:block_is_given
else
# do other stuff
:block_not_given
end
end
end
end

A.new.a # => :block_not_given
A.new.a { “Hello World” } # => :block_is_given

3

Thanks, that solve the problem.