Suppose a user submits a url: http://www.nyt.com/education/2345545. How can this be shortened to a cleaner url, like nyt.com?
on 2009-05-28 10:57
on 2009-05-28 12:12
require 'uri' uri = URI.parse("http://www.ruby-lang.org/") p uri # => #<URI::HTTP:0x202281be URL:http://www.ruby-lang.org/> p uri.scheme # => "http" p uri.host # => "www.ruby-lang.org" http://www.ruby-doc.org/core/classes/URI.html
on 2009-05-28 14:16
Mukund wrote: > require 'uri' > > uri = URI.parse("http://www.ruby-lang.org/") > p uri > # => #<URI::HTTP:0x202281be URL:http://www.ruby-lang.org/> > p uri.scheme > # => "http" > p uri.host > # => "www.ruby-lang.org" > > http://www.ruby-doc.org/core/classes/URI.html This is a little harder than I expected. So I include the require 'uri' in the model. Then it seems I need to parse the host part of the uri. How do I parse this? Do I need to use a RegExpression?
on 2009-05-28 15:01
Sean, Are you saving this url to the model? I'm not sure what you mean by shorten it up? --Tom
on 2009-05-28 18:19
tomrossi7 wrote: > Sean, > > Are you saving this url to the model? I'm not sure what you mean by > shorten it up? > > --Tom I want a user to submit a link to a webpage. After they submit the link I want to parse it to the homepage url. Like if the article is www.nyt.com/sports/lakers/123. I want to have this shortened to the homepage link nyt.com. You can try it in the interpreter as someone posted above.
on 2009-05-28 18:48
Yeah, URI is the library to work with. You could tighten it up and just do: homepage = URI.parse("http://www.nyt.com/sports/lakers/123/").host On the model, you could put "require 'uri' " but I think its loaded with Rails by default. --Tom I don't think On May 28, 12:19 pm, Sean Six <rails-mailing-l...@andreas-s.net>
on 2009-05-29 05:52
I have @article.url and I want to parse that url. When I tried: @homepage = URI.parse(@article.url).host in the controller I simply got a blank output.
on 2009-06-01 17:13
Can you post a sample @article.url that results in blank .host output from URI.parse?