We are trying to convert “image1.txt” file which is a binary file to
“image1.bmp” file usng Ruby + RMagick2.0 but not able to get the
required output that is “Menu.bmp”. Following the attached code that we
have reached so far. Look forward to get some help as how to get an
output like “Menu.bmp” from the file called “image1.txt”
I was not able to attached all the three files ( image1.txt, image1.bmp
and Menu.bmp) So just attached the source file “image1.txt” and if you
run the following case, it wll generate “image1.bmp”
require ‘rmagick’
file_name = “C:/image1.text” # the binary file
image_file_name = “C:/image1.bmp” # the expected file to be generated
image = Magick::Image.new(704, 480)
file = File.read(file_name)
#=begin
one = []
two = []
three = []
p = 0
l = 1
file.each_byte { |x|
case l
when 1
one << x
#getOne=((moveOne << 1 + 16) >> 11 + 16)
#one << getOne
l += 1
when 2
two << x
#getTwo=((moveTwo << 6 + 16) >> 11 + 16)
#two << getTwo
l += 1
when 3
three << x
#getThree=((moveThree << 11 + 16) >> 11 + 16)
#three << getThree
p += 1
#puts “#{one} #{two} #{three}”
l = 1
end
}
bufferscreen_height=480
bufferscreen_width=704
k=0
for i in 0…bufferscreen_height
#puts “Height: #{i} \n\n”
for j in 0…bufferscreen_width
#puts “Width: #{j} \n\n”
#q=Magick::Pixel.new(25,75,34, 0)
q=Magick::Pixel.new(one[k],two[k],three[k],0)
#q=Magick::Pixel.new(((one[k] << 17) >> 27), ((two[k] << 22) >> 27),
((three[k] << 27) >> 27), 0)
#puts “R:#{one[k]} G:#{two[k]} B:#{three[k]}”
#puts “\n\n”
#y, z = p.divmod(704)
image.pixel_color(j,i,q)
k += 1
end
end
image.write(image_file_name)
#=end