Alias_method code snippet doubt

Ruby
1

module Mod
alias_method :orig_exit, :exit
def exit(code=0)
puts “Exiting with code #{code}”
orig_exit(code)
end
end
include Mod
exit(99)

Above snippet we are creating new alias (orig_exit) for already
existing method exit. Interesting thing is orig_exit is again called
in exit method, why won’t this behavior cause recursive calling of
method it self since orig_exit is simply alias to exit method ?

2

On 5/30/07, Googy [email protected] wrote:

Above snippet we are creating new alias (orig_exit) for already
existing method exit. Interesting thing is orig_exit is again called
in exit method, why won’t this behavior cause recursive calling of
method it self since orig_exit is simply alias to exit method ?

This is a pattern how to preserve original method that you want to
override.
Alias stores the method as it was when alias was called. When you
override the method, the alias stil points to the old version –
that’s the point of this construct.

J.

3

On May 30, 1:37 pm, “Jano S.” [email protected] wrote:

end
override the method, the alias stil points to the old version –
that’s the point of this construct.

J.

Thanks I am now able to understand whats going on, Until now I used to
assume like alias’ed method and original method point to single
version of method.

Thanks for clarifying.