Hi,
I’m struggeling with writing a little script. It has a loop just e.g.
like this:
for x in 1…10 do
begin
puts “#{x}”
end
The userinput is the loop count (so above the userinput would have been
1…10): but now this userinput can be a fixnum like 12 or 36 or it can
be a range like 1…10 or 24…84 or an array like [23,41,35,63] and for
every 3 different input kinds the loop shall do the same.
Like in this example:
If userinput is just fixnum 11 it just prints 11 on the screen, is it a
range from 1…10 all numbers from 1…10 shall be printed and for an
array all single numbers stored in the array…you know what I mean. The
actual routine doesn’t print anything it’s just about I have to process
numbers which can the user give in, in three different ways and I was
wondering if it is possible to build this into one single loop and not
three different ones?
–
greets
(
)
(
/\ .-"""-. /\
//\\/ ,,, \//\\
|/\| ,;;;;;, |/\|
//\\\;-"""-;///\\
// \/ . \/ \\
(| ,-_| \ | / |_-, |)
//`__\.-.-./__`\\
// /.-(() ())-.\ \\
(\ |) '---' (| /)
` (| |) `
jgs \) (/
one must still have chaos in oneself to be able to give birth to a
dancing star
On 06.05.2007 15:20, anansi wrote:
1…10): but now this userinput can be a fixnum like 12 or 36 or it can
wondering if it is possible to build this into one single loop and not
three different ones?
How about
def my_loop(x,&b)
case x
when /\A\d+\z/
x.to_i.times(&b)
when /\A(\d+)…(\d+)\z/
($1.to_i … $2.to_i).each(&b)
when /\A[\s*\d+\s*(?:,\s*\d+\s*)*]\z/
eval(x).each(&b)
else
raise ArgumentError, “Don’t know what to do with: #{x}”
end
end
my_loop(“5”) {|x| p x}
0
1
2
3
4
=> 5
my_loop(“1…5”) {|x| p x}
1
2
3
4
5
=> 1…5
my_loop("[5,3,2]") {|x| p x}
5
3
2
=> [5, 3, 2]
my_loop(“1,2”) {|x| p x}
ArgumentError: Don’t know what to do with: 1,2
from (irb):10:in `my_loop’
from (irb):16
from :0
Kind regards
robert
anansi wrote:
been 1…10): but now this userinput can be a fixnum like 12 or 36 or
and I was wondering if it is possible to build this into one single
loop and not three different ones?
Assuming that userinput can only be a Range, Array, or Fixnum…both
Range and Array have an each method. Test userinput to see if it
responds to :each. If it does, you’re golden. If it doesn’t, it’s a
Fixnum. Make an array from the Fixnum by calling Array(). Now iterate
over the result using :each. (This is untested but it’ll give you an
idea of what to do.)
userinput = Array(userinput) unless userinput.respond_to? :each
userinput.each do |x|
puts x
end
P.S. the puts method converts its argument to a string. You don’t need
to use “#{x}”.
On 06.05.2007 15:30, Robert K. wrote:
The userinput is the loop count (so above the userinput would have
process numbers which can the user give in, in three different ways
($1.to_i … $2.to_i).each(&b)
2
my_loop("[5,3,2]") {|x| p x}
Kind regards
robert
more elegant:
def my_loop(x,&b)
case x
when /\A\d+\z/
1 … x.to_i
when /\A(\d+)…(\d+)\z/
($1.to_i … $2.to_i)
when /\A[\s*\d+\s*(?:,\s*\d+\s*)*]\z/
eval(x)
else
raise ArgumentError, “Don’t know what to do with: #{x}”
end.each(&b)
end
more modular:
def my_enum(x,&b)
case x
when /\A\d+\z/
1 … x.to_i
when /\A(\d+)…(\d+)\z/
($1.to_i … $2.to_i)
when /\A[\s*\d+\s*(?:,\s*\d+\s*)*]\z/
eval(x)
else
raise ArgumentError, “Don’t know what to do with: #{x}”
end
end
robert
Hi thank you both 
I took Tim’s answer because it’s faster and much smaller and my loop had
some timeout-problems with the case-when method to solve it.
Tim H. wrote:
The userinput is the loop count (so above the userinput would have
process numbers which can the user give in, in three different ways
userinput = Array(userinput) unless userinput.respond_to? :each
userinput.each do |x|
puts x
end
P.S. the puts method converts its argument to a string. You don’t need
to use “#{x}”.
–
greets
(
)
(
/\ .-"""-. /\
//\\/ ,,, \//\\
|/\| ,;;;;;, |/\|
//\\\;-"""-;///\\
// \/ . \/ \\
(| ,-_| \ | / |_-, |)
//`__\.-.-./__`\\
// /.-(() ())-.\ \\
(\ |) '---' (| /)
` (| |) `
jgs \) (/
one must still have chaos in oneself to be able to give birth to a
dancing star