# Strings - trying to trim values

**URL:** <https://www.ruby-forum.com/t/strings-trying-to-trim-values/158391>\
**Category:** Ruby\
**Created:** [January 22, 2009, 9:11pm UTC](https://www.ruby-forum.com/t/strings-trying-to-trim-values/158391 "2009-01-22T21:11:14Z")\
**Posts on this page:** 3\
**Page:** 1

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**Author:** ![mmcolli00](https://www.ruby-forum.com/letter_avatar_proxy/v4/letter/m/85e7bf/32.png) [@mmcolli00](https://www.ruby-forum.com/u/mmcolli00)\
**Post date:** [January 22, 2009, 9:11pm UTC](https://www.ruby-forum.com/t/strings-trying-to-trim-values/158391/1 "2009-01-22T21:11:14Z")

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What is the correct way to trim off the the first 37 characters of a  
string?

I want to trim off the value from position 0 -\> pos 37 or take off all  
characters from right side and stopping at a specific character #.

myval = wererwerwerwerweritop123233434345556#personID

How is this done? Thanks.  
MC

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**Author:** ![mmcolli00](https://www.ruby-forum.com/letter_avatar_proxy/v4/letter/m/85e7bf/32.png) [@mmcolli00](https://www.ruby-forum.com/u/mmcolli00)\
**Post date:** [January 22, 2009, 9:24pm UTC](https://www.ruby-forum.com/t/strings-trying-to-trim-values/158391/2 "2009-01-22T21:24:46Z")

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On Jan 22, 2009, at 3:09 PM, Mmcolli00 Mom wrote:

> –  
> Several ways:

irb\> myval = ‘wererwerwerwerweritop123233434345556#personID’  
=\> “wererwerwerwerweritop123233434345556#personID”  
irb\> myval[37…-1]  
=\> “personID”  
irb\> myval.split(‘#’,2).last  
=\> “personID”  
irb\> myval[/[^#]\*\z/]  
=\> “personID”

Take your pick!

-Rob

Rob B. [http://agileconsultingllc.com](http://agileconsultingllc.com)  
removed\_email\_address@domain.invalid

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**Author:** ![mmcolli00](https://www.ruby-forum.com/letter_avatar_proxy/v4/letter/m/85e7bf/32.png) [@mmcolli00](https://www.ruby-forum.com/u/mmcolli00)\
**Post date:** [January 23, 2009, 4:01am UTC](https://www.ruby-forum.com/t/strings-trying-to-trim-values/158391/3 "2009-01-23T04:01:29Z")

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Thanks Rob!
