# Spliting hash using map! **URL:** \ **Category:** Ruby\ **Created:** [October 12, 2009, 12:14pm UTC](https://www.ruby-forum.com/t/spliting-hash-using-map/177142 "2009-10-12T12:14:54Z")\ **Posts on this page:** 6\ **Page:** 1
**Author:** ![nescripter](https://www.ruby-forum.com/letter_avatar_proxy/v4/letter/n/2acd7d/32.png) [@nescripter](https://www.ruby-forum.com/u/nescripter)\ **Post date:** [October 12, 2009, 12:14pm UTC](https://www.ruby-forum.com/t/spliting-hash-using-map/177142/1 "2009-10-12T12:14:54Z")
Hello, I have a program which goes through a number of entries, a typical example of these entries is as follows: qwerty 0001 abcdef 0002 0003 0004 uvwxyz 0005 0006 Basically, the first string can match to one or more unique numbers. This structure is a hash. Later in my code I remove the string leaving only the numbers, I then wish to break the numbers down into their individual items, I use map! (output = ID.map!{|str| str.split(/\s+/) }.flatten!) to do this giving 0001 000200030004 00050006 What I want to do at this stage is have them broken into individual items instead of a full string for each, the purpose of this is so I can do something like this: if 0001.match(/#{output}/) puts output end So in a loop for the second entry we would be doing if 0001.match(/#{0002}/)… if 0001.match(/#{0003}/) and so on At this stage I am not getting that result because I do not have 0002, 0003 and so on, I only have individual entries from the hash such as 1. Could anyone assist me with this query? Sorry if it is unclear, and may thanks for your help. ---
**Author:** ![nescripter](https://www.ruby-forum.com/letter_avatar_proxy/v4/letter/n/2acd7d/32.png) [@nescripter](https://www.ruby-forum.com/u/nescripter)\ **Post date:** [October 12, 2009, 1:11pm UTC](https://www.ruby-forum.com/t/spliting-hash-using-map/177142/2 "2009-10-12T13:11:04Z")
2009/10/12 Ne Scripter [removed\_email\_address@domain.invalid](mailto:removed_email_address@domain.invalid): > Sorry if it is unclear, and may thanks for your help. I am at a loss here. Can you provide a more complete example which demonstrates what you’re after? Kind regards robert ---
**Author:** ![nescripter](https://www.ruby-forum.com/letter_avatar_proxy/v4/letter/n/2acd7d/32.png) [@nescripter](https://www.ruby-forum.com/u/nescripter)\ **Post date:** [October 12, 2009, 1:19pm UTC](https://www.ruby-forum.com/t/spliting-hash-using-map/177142/3 "2009-10-12T13:19:16Z")
Hi, * * * On Monday 12 October 2009 07:14:57 Ne Scripter wrote: > individual items, I use map! (output = ID.map!{|str| str.split(/\s+/) > }.flatten!) to do this giving > > 0001 > 000200030004 > 00050006 If you are to put the result of map in ‘output’ the you don’t need map!, just map. You also don’t need flatten!, just flatten. And, BTW, where does ID come from? What is ID, an array, a string? ## – angico Site: [angico.org](http://angico.org) Blog: [angico.org/blog](http://angico.org/blog) Gnu/Linux, FLOSS, Espiritismo, e eu por mim mesmo 8^I == Cooperação é _muito_ melhor que competição == ---
**Author:** ![nescripter](https://www.ruby-forum.com/letter_avatar_proxy/v4/letter/n/2acd7d/32.png) [@nescripter](https://www.ruby-forum.com/u/nescripter)\ **Post date:** [October 12, 2009, 3:18pm UTC](https://www.ruby-forum.com/t/spliting-hash-using-map/177142/4 "2009-10-12T15:18:21Z")
Sorry for being unclear. Basically, if I say the following string = “0002 0003 0004 0005” if 0002.match(/#{string}/) puts string end So I want to say if my string contains the item given in the IF statement tell me the item that it found, in the example above 0002. The code I have above does not match anything. Thanks angico wrote: > Hi, > > * * * > > On Monday 12 October 2009 07:14:57 Ne Scripter wrote: > > > individual items, I use map! (output = ID.map!{|str| str.split(/\s+/) > > }.flatten!) to do this giving > > > > 0001 > > 000200030004 > > 00050006 > > If you are to put the result of map in ‘output’ the you don’t need map!, > just > map. You also don’t need flatten!, just flatten. > > And, BTW, where does ID come from? What is ID, an array, a string? > > ## – angico > > Site: [angico.org](http://angico.org) > Blog: [angico.org/blog](http://angico.org/blog) > > Gnu/Linux, FLOSS, Espiritismo, e eu por mim mesmo 8^I > > == Cooperação é _muito_ melhor que competição == ---
**Author:** ![nescripter](https://www.ruby-forum.com/letter_avatar_proxy/v4/letter/n/2acd7d/32.png) [@nescripter](https://www.ruby-forum.com/u/nescripter)\ **Post date:** [October 12, 2009, 3:37pm UTC](https://www.ruby-forum.com/t/spliting-hash-using-map/177142/5 "2009-10-12T15:37:40Z")
Solved. I went for string.include?(variable) Thanks > angico wrote: > > > Hi, > > > > * * * > > > > On Monday 12 October 2009 07:14:57 Ne Scripter wrote: > > > > > individual items, I use map! (output = ID.map!{|str| str.split(/\s+/) > > > }.flatten!) to do this giving > > > 0001 > > > 000200030004 > > > 00050006 > > > If you are to put the result of map in ‘output’ the you don’t need map!, > > > just > > > map. You also don’t need flatten!, just flatten. > > > > And, BTW, where does ID come from? What is ID, an array, a string? > > > > ## – angico ---
**Author:** ![nescripter](https://www.ruby-forum.com/letter_avatar_proxy/v4/letter/n/2acd7d/32.png) [@nescripter](https://www.ruby-forum.com/u/nescripter)\ **Post date:** [October 12, 2009, 3:48pm UTC](https://www.ruby-forum.com/t/spliting-hash-using-map/177142/6 "2009-10-12T15:48:31Z")
Ne Scripter wrote: > Sorry for being unclear. > > Basically, if I say the following > > string = “0002 0003 0004 0005” > > if 0002.match(/#{string}/) > puts string > end > > So I want to say if my string contains the item given in the IF > statement tell me the item that it found, in the example above 0002. > > The code I have above does not match anything. Your regex is /0002 0003 0004 0005/. That pattern does not appear in the string “0002” (and the integer 0002 does not have a match() method!). Look at this example: string = “0002 0003 0004 0005” if string.match(/0002/) puts string end –output:– 0002 0003 0004 0005 In this example, the regex is /0002/, and that patter does occur in the string “0002 0003 0004 0005”, so there is a match.