Ruby For Rails Bind and Unbind question

Rails
1

When I run the following example:

class A
def a_method
puts “Definition in class A”
end
end
class B < A
def a_method
puts “Definition in class B (subclass of A)”
end
end
class C
def call_original
A.instance_method(:a_method).bind(self).call
end
end
c = C.new
c.call_original

I get the following error:

TypeError: bind argument must be an instance of A

method bind in c.rb at line 13
method call_original in c.rb at line 13
at top level in c.rb at line 17

Can someone please tell me why it is failing? TIA.

2

Hi –

On Tue, 10 Oct 2006, Bala P. wrote:

puts “Definition in class B (subclass of A)”
I get the following error:

TypeError: bind argument must be an instance of A

You’ve combined two related examples, but you’ve left out an important
bit:

class C < B
end

(on page 358) The class C declaration on p. 359 is a reopening of C,
so it doesn’t have the < B part. If you want to do it all together,
just change “class C” to “class C < B”.

David

–
David A. Black | [email protected]
Author of “Ruby for Rails” [1] | Ruby/Rails training & consultancy [3]
DABlog (DAB’s Weblog) [2] | Co-director, Ruby Central, Inc. [4]
[1] Ruby for Rails | [3] http://www.rubypowerandlight.com
[2] http://dablog.rubypal.com | [4] http://www.rubycentral.org

3

Thank you. In the book example on const_missing, why does the output
print 1 twice?

class C
def self.const_missing(const)
puts “#{const} is undefinedâ??setting it to 1.”
const_set(const,1)
end
end
puts C::A
puts C::A

4

Why wouldn’t it?

The first puts statement calls const_missing() which returns 1 via
const_set(). puts takes it and prints it. The second time puts is
called, C::A is defined to 1, so the statement functions as you would
expect it.