# Python Vs Ruby ( again )

**URL:** <https://www.ruby-forum.com/t/python-vs-ruby-again/110469>\
**Category:** Ruby\
**Created:** [July 26, 2007, 4:53pm UTC](https://www.ruby-forum.com/t/python-vs-ruby-again/110469 "2007-07-26T16:53:51Z")\
**Posts on this page:** 1\
**Page:** 1

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**Author:** ![bpauly](https://www.ruby-forum.com/letter_avatar_proxy/v4/letter/b/ecd19e/32.png) [@bpauly](https://www.ruby-forum.com/u/bpauly)\
**Post date:** [July 26, 2007, 4:53pm UTC](https://www.ruby-forum.com/t/python-vs-ruby-again/110469/1 "2007-07-26T16:53:51Z")

</div>

There was a discussion a while back in trying to get Ruby looking like  
Python using an indentation scheme and I posted a possible solution to  
that

[http://xtargets.com/snippets/posts/show/68](http://xtargets.com/snippets/posts/show/68)

There is also the Lazibi library ( sorry no link … google it ) that  
does a similar thing.

I thought to be fair I’d have a hack in the opposite direction and see  
if I could emulate Ruby’s block notation in Python without  
preprocessing. Turns out that you can get pretty close though if a bit  
ugly due to the statement vs expression nature of the language.

Note that in python a return statement from within a function with a  
yield statement is illegal some some ugly workaround is necessary.

A few short examples …

from ruby import rubyfi

#Ruby’s inject method  
@rubyfi  
def inject(ret, iter, a = 0):  
for x in iter:  
a = yield a, x  
ret(a)

#Ruby’s collect method  
@rubyfi  
def collect(ret, iter):  
r = []  
for x in iter:  
x = yield x,  
r.append(x)  
ret(r)

# Do a sum over a range

for r, s, x in inject ( range (1,6), 1 ) :  
r(s+x)  
print r()

# Generate a list

for r, s, x in inject ( range (1,6), [] ) :  
s.append(x\*x)  
r(s)  
print r()

# Collect some items

for r, x in collect ( range (1,6) ) :  
r(x+x)  
print r()

The library and some details is at

[http://xtargets.com/snippets/posts/show/74](http://xtargets.com/snippets/posts/show/74)

Can this be developed a little further or a little cleaner?