On 25-Oct-07, at 1:57 PM, Robert D. wrote:
the program was
endRuby allocated up to 43M and then decided to release 3M regularly,
seems a very reasonable strategy to me.
I feel that it would be nice to show the exact leaking code so that I
can run it.
You need to be careful what it is you are testing.
Try the tiny variation I’ve supplied below as it is, it’ll execute
relatively benignly. Then comment out the crucial line indicated by
the comment. If you dare. BTW, if you run this make sure you keep on
top of things and kill it before it starts screwing up your machine.
Make sure you don’t have anything important unsaved.
Why don’t we keep all the ‘a’ arrays we generate? Shouldn’t cause a
problem right? If fact if you don’t comment out the crucial line
memory use will grow relatively slowly. If you do comment it out,
then, well, it is your machine.
BTW, the only thing special about nil is that there is only one of
them. You could use a symbol, true/false, a number – just don’t
create a new object.
What happens if you comment out the whole second N.times loop? I get
strangely similar behaviour to just commenting out the crucial line.
Why’s that? Because, in neither case, none of the arrays of Object is
being collected.
If you get the behaviour I’m getting, how do you explain it other
than as a leak?
Innocent bystanders: if you comment out that crucial line before
running the program PAY ATTENTION AND BE READY TO KILL THE PROCESS
BEFORE IT LOCKS UP YOUR MACHINE (very bad on OS X, it is an abrupt
lockup of the system after about 20s on my machine, Ctrl-C won’t
work, get either your activity monitor up and visible or the force
quit dialog).
N = 1000
M = 1000
as = []
loop do
a = []
N.times do
a << Array.new( M ){ Object.new }
end
N.times do
a[0] = nil # <<< the crucial line
a.shift
end
as << a
GC.start
STDERR << ‘.’
end
Cheers,
Bob
–
what do I think about Ruby?
http://ruby-smalltalk.blogspot.com/
Bob H. – tumblelog at http://
www.recursive.ca/so/
Recursive Design Inc. – weblog at http://www.recursive.ca/
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