# Ofdm channel estimation

**URL:** <https://www.ruby-forum.com/t/ofdm-channel-estimation/231250>\
**Category:** GNU Radio\
**Created:** [July 30, 2014, 11:13am UTC](https://www.ruby-forum.com/t/ofdm-channel-estimation/231250 "2014-07-30T11:13:40Z")\
**Posts on this page:** 2\
**Page:** 1

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**Author:** ![addis\_a](https://www.ruby-forum.com/letter_avatar_proxy/v4/letter/a/c4cdca/32.png) [@addis\_a](https://www.ruby-forum.com/u/addis_a)\
**Post date:** [July 30, 2014, 11:13am UTC](https://www.ruby-forum.com/t/ofdm-channel-estimation/231250/1 "2014-07-30T11:13:40Z")

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Hi Martin:  
Greeting from xd.Thank you so much for your example  
tx\_ofdm.grc and rx\_ofdm.grc.I want to ask a question about channel  
estimation.And I know that the channel estimate is on a tag.But I want  
to make some changes on your example.So I just want to ask whether my  
understanding is right or not.  
I know the rx\_ofdm include “header stream” and “payload  
stream”.In the “payload stream”,if i denote the data come from FFT block  
“rx\_data”.  
channel=rx\_data/tx\_data  
Is it right?Is my understanding right?Thank you.  
Best regards,  
xd

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**Author:** ![xianda](https://www.ruby-forum.com/letter_avatar_proxy/v4/letter/x/b38774/32.png) [@xianda](https://www.ruby-forum.com/u/xianda)\
**Post date:** [July 30, 2014, 4:05pm UTC](https://www.ruby-forum.com/t/ofdm-channel-estimation/231250/2 "2014-07-30T16:05:41Z")

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On 07/30/2014 10:57 AM, xianda wrote:

> ```
> Is it right?Is my understanding right?Thank you.
> 
> ```

Yep.

M