# Is there any correlation between bandwidth and subcarriers-tounes in ofdm?

**URL:** <https://www.ruby-forum.com/t/is-there-any-correlation-between-bandwidth-and-subcarriers-tounes-in-ofdm/227743>\
**Category:** GNU Radio\
**Created:** [March 27, 2013, 10:55am UTC](https://www.ruby-forum.com/t/is-there-any-correlation-between-bandwidth-and-subcarriers-tounes-in-ofdm/227743 "2013-03-27T10:55:55Z")\
**Posts on this page:** 3\
**Page:** 1

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**Author:** ![Yingjie\_C](https://www.ruby-forum.com/letter_avatar_proxy/v4/letter/y/f14d63/32.png) [@Yingjie\_C](https://www.ruby-forum.com/u/Yingjie_C)\
**Post date:** [March 27, 2013, 10:55am UTC](https://www.ruby-forum.com/t/is-there-any-correlation-between-bandwidth-and-subcarriers-tounes-in-ofdm/227743/1 "2013-03-27T10:55:55Z")

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Hi guys,

I wonder if there is any correlation between baseband bandwidth of  
receiver side and fft-subcarriers-tounes of sender sider in OFDM? When  
I set the bandwidth to 20Mhz in sender side, the spectrum analyzer of  
receiver side shows only half of bandwidth（10Mhz). Does the reason  
that I use 128fft and 64 subcarriers account for this phenomenon?

Sent from my iPhone

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**Author:** ![Yingjie\_C](https://www.ruby-forum.com/letter_avatar_proxy/v4/letter/y/f14d63/32.png) [@Yingjie\_C](https://www.ruby-forum.com/u/Yingjie_C)\
**Post date:** [March 27, 2013, 11:04am UTC](https://www.ruby-forum.com/t/is-there-any-correlation-between-bandwidth-and-subcarriers-tounes-in-ofdm/227743/2 "2013-03-27T11:04:41Z")

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The fraction of the Nyquist zone occupied is equal to the number of  
active tones divided by the FFT length. The actual bandwidth then  
depends on your sampling rate.

MB

On Wed, Mar 27, 2013 at 05:54:46PM +0800, Yingjie C. wrote:

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**Author:** ![Yingjie\_C](https://www.ruby-forum.com/letter_avatar_proxy/v4/letter/y/f14d63/32.png) [@Yingjie\_C](https://www.ruby-forum.com/u/Yingjie_C)\
**Post date:** [March 27, 2013, 12:47pm UTC](https://www.ruby-forum.com/t/is-there-any-correlation-between-bandwidth-and-subcarriers-tounes-in-ofdm/227743/3 "2013-03-27T12:47:35Z")

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Thanks for your reply. You mean the bandwidth in receiver side(spectrum  
analyser) is only half of that of sender side if the active tones is  
half  
of the FFT length, is that right? Can you provide the explicit formula  
for  
helping me better understand.

2013/3/27 Martin B. (CEL) [removed\_email\_address@domain.invalid](mailto:removed_email_address@domain.invalid)
