# How to trim the 0 **URL:** \ **Category:** Rails\ **Created:** [October 11, 2007, 12:29pm UTC](https://www.ruby-forum.com/t/how-to-trim-the-0/116934 "2007-10-11T12:29:17Z")\ **Posts on this page:** 9\ **Page:** 1
**Author:** ![vidyagayathri](https://www.ruby-forum.com/letter_avatar_proxy/v4/letter/v/ba9def/32.png) [@vidyagayathri](https://www.ruby-forum.com/u/vidyagayathri)\ **Post date:** [October 11, 2007, 12:29pm UTC](https://www.ruby-forum.com/t/how-to-trim-the-0/116934/1 "2007-10-11T12:29:17Z")
hi all, I want to remove o, which is present in the before statement, like @a=EDIA00050 (in this EDIA is common) @t=@a.spilt(“EDIA”) render\_text @t[1] so i will get the output like 000050, but i want 50 only, like this this record will be change 000150,001150 so i want to remove which is in front of the element ‘o’ it should not remove ‘0’, which is back, please let me know , how to do this. ---
**Author:** ![vidyagayathri](https://www.ruby-forum.com/letter_avatar_proxy/v4/letter/v/ba9def/32.png) [@vidyagayathri](https://www.ruby-forum.com/u/vidyagayathri)\ **Post date:** [October 11, 2007, 12:40pm UTC](https://www.ruby-forum.com/t/how-to-trim-the-0/116934/2 "2007-10-11T12:40:35Z")
On 11 Oct 2007, at 11:29, Vidya V. wrote: > hi all, > > I want to remove o, which is present in the before statement, like > > @a=EDIA00050 (in this EDIA is common) > @t=@a.spilt(“EDIA”) > render\_text @t[1] a =~ /0\*([1-9]\d\*)/ puts $1 Fred ---
**Author:** ![vidyagayathri](https://www.ruby-forum.com/letter_avatar_proxy/v4/letter/v/ba9def/32.png) [@vidyagayathri](https://www.ruby-forum.com/u/vidyagayathri)\ **Post date:** [October 11, 2007, 12:47pm UTC](https://www.ruby-forum.com/t/how-to-trim-the-0/116934/3 "2007-10-11T12:47:00Z")
hi Fred, thanks for your reply, but i don’t know how to apply in my coding, can you tell me Frederick C. wrote: > On 11 Oct 2007, at 11:29, Vidya V. wrote: > > > hi all, > > > > I want to remove o, which is present in the before statement, like > > > > @a=EDIA00050 (in this EDIA is common) > > @t=@a.spilt(“EDIA”) > > render\_text @t[1] > > a =~ /0\*([1-9]\d\*)/ > puts $1 > > Fred ---
**Author:** ![vidyagayathri](https://www.ruby-forum.com/letter_avatar_proxy/v4/letter/v/ba9def/32.png) [@vidyagayathri](https://www.ruby-forum.com/u/vidyagayathri)\ **Post date:** [October 11, 2007, 1:14pm UTC](https://www.ruby-forum.com/t/how-to-trim-the-0/116934/4 "2007-10-11T13:14:50Z")
Vidya V. wrote: > hi all, > > I want to remove o, which is present in the before statement, like > > @a=EDIA00050 (in this EDIA is common) > @t=@a.spilt(“EDIA”) > render\_text @t[1] gsub: [http://www.ruby-doc.org/core/classes/String.html#M000832](http://www.ruby-doc.org/core/classes/String.html#M000832) @a=EDIA00050 (in this EDIA is common) # this will work given that the string always starts with EDIA and follows immediately with 0 or more zero’s. @t=@a.gsub(/^EDIA0\*/, ‘’) render\_text @t[1] i’d advise looking into regexp a little deeper if this seems odd to you. > **[Regular expression | Syntax](https://en.wikipedia.org/wiki/Regular_expression#Syntax)** > > A regex pattern matches a target string. The pattern is composed of a sequence of atoms. An atom is a single point within the regex pattern which it tries to match to the target string. The simplest atom is a literal, but grouping parts of the pattern to match an atom will require using ( ) as metacharacters. Metacharacters help form: atoms; quantifiers telling how many atoms (and whether it is a greedy quantifier or not); a logical OR character, which offers a set of alternatives, and a logical ... hope it helps! shai ---
**Author:** ![vidyagayathri](https://www.ruby-forum.com/letter_avatar_proxy/v4/letter/v/ba9def/32.png) [@vidyagayathri](https://www.ruby-forum.com/u/vidyagayathri)\ **Post date:** [October 11, 2007, 1:21pm UTC](https://www.ruby-forum.com/t/how-to-trim-the-0/116934/5 "2007-10-11T13:21:33Z")
Thank you so much shai, it works well ---
**Author:** ![vidyagayathri](https://www.ruby-forum.com/letter_avatar_proxy/v4/letter/v/ba9def/32.png) [@vidyagayathri](https://www.ruby-forum.com/u/vidyagayathri)\ **Post date:** [October 11, 2007, 2:25pm UTC](https://www.ruby-forum.com/t/how-to-trim-the-0/116934/6 "2007-10-11T14:25:50Z")
On 10/11/07, Shai R. [removed\_email\_address@domain.invalid](mailto:removed_email_address@domain.invalid) wrote: > gsub: > [class String - RDoc Documentation](http://www.ruby-doc.org/core/classes/String.html#M000832) > > @a=EDIA00050 (in this EDIA is common) > > # this will work given that the string always starts with EDIA and > > follows immediately with 0 or more zero’s. > @t=@a.gsub(/^EDIA0\*/, ‘’) > render\_text @t[1] And if you don’t need to save the value in an instance variable just: ``` render_text @a.gsub(/^EDIA0*/, '') ``` I’ve got no idea what @a and @t represent, or whether they should really BE instance variables or locals. One strong suggestion to the OP is to use meaningful variable names. – Rick DeNatale My blog on Ruby [http://talklikeaduck.denhaven2.com/](http://talklikeaduck.denhaven2.com/) ---
**Author:** ![vidyagayathri](https://www.ruby-forum.com/letter_avatar_proxy/v4/letter/v/ba9def/32.png) [@vidyagayathri](https://www.ruby-forum.com/u/vidyagayathri)\ **Post date:** [October 11, 2007, 3:56pm UTC](https://www.ruby-forum.com/t/how-to-trim-the-0/116934/7 "2007-10-11T15:56:34Z")
Shai R. wrote: > @t=@a.gsub(/^EDIA0\*/, ‘’) gsub does the job, but match is designed to return parts of a string that “match”: EDIA\_ID = /[1-9]\d\*$/ @t = @a.match(EDIA\_ID)[0] =\>“50” …and can be used to get multiple matches at a time, which is sometimes useful (though probably not in this case): EDIA\_PARTS = /^(._)([1-9]\d_)$/ all, prefix, edia\_id = a.match(EDIA\_PARTS).captures =\> [“EDIA00050”, “EDIA000”, “50”] edia\_id =\> “50” match returns a MatchData object whose “matches” can be accessed with the [] method – like an array (though you have to use captures or to\_a to actually get an array). [0] returns the entire data matched, and [1]+ return the parenthetical submatches (like a regular expression replace string with \1 or $1 backreferenced subpatterns). The MatchData object also retains information about where the matches were found in the original string which can be accessed later with various methods. ---
**Author:** ![vidyagayathri](https://www.ruby-forum.com/letter_avatar_proxy/v4/letter/v/ba9def/32.png) [@vidyagayathri](https://www.ruby-forum.com/u/vidyagayathri)\ **Post date:** [October 11, 2007, 4:46pm UTC](https://www.ruby-forum.com/t/how-to-trim-the-0/116934/8 "2007-10-11T16:46:16Z")
hi vidya, I think, simply u can also use like below for this scenario: “@t[1].to\_i” this will return the integer value right i.e 50 Regards, P.Gokula murthy ---
**Author:** ![vidyagayathri](https://www.ruby-forum.com/letter_avatar_proxy/v4/letter/v/ba9def/32.png) [@vidyagayathri](https://www.ruby-forum.com/u/vidyagayathri)\ **Post date:** [October 11, 2007, 2:34pm UTC](https://www.ruby-forum.com/t/how-to-trim-the-0/116934/9 "2007-10-11T14:34:07Z")
Thanks for your suggestion, i try to use meaningful words