# Forum: Ruby Euchre Hands (#55)

Announcement (2017-05-07): www.ruby-forum.com is now read-only since I unfortunately do not have the time to support and maintain the forum any more. Please see rubyonrails.org/community and ruby-lang.org/en/community for other Rails- und Ruby-related community platforms.
on 2005-11-21 10:03
```All,

This quiz looked so simple I just couldn't resist putting in the
short amount of time needed to solve it.  Also, I love to play Euchre.

I see other solutions trying very hard to make sure that two suits
of the same color do not appear next to each other.  As a Euchre player,
I would be quite upset if the order of the suits changed during play.
For example, if hearts were trump, and the hand is (9h 9s 9d 9c Tc), and
the 9s is played, the hand should stay (9h 9d 9c Tc), not be reordered
to (9h 9c Tc 9d).  I tend to always keep my suits in the same order (s h
c d) and simply rotate the order so that the trump suit is first (e.g.
(c d s h) if clubs are trump).

I also made sure the routine works with fewer (or more) than five
cards since cards are actually played from the hand during a game.

----------------------------------------------------------------
# Constants
RANKS = 'AKQJT9'
SUITS = 'SHCD'

def euchre_sort(cards)
# Split out trump
trump = cards.shift

# Quick and dirty validation
trump_index = SUITS.index(trump[0,1].upcase)
unless trump_index
puts "Invalid trump (#{trump})."
exit
end
cards.each do |card|
if card !~ /^[#{RANKS}][#{SUITS}]\$/i
puts "Invalid card (#{card})."
exit
end
end

# Return sorted hand
right_bower = "J#{SUITS[trump_index,1]}"
left_bower = "J#{SUITS[trump_index - 2,1]}"
[trump] +
cards.sort_by do |card|
upcase_card = card.upcase
case upcase_card
when right_bower then -2
when left_bower  then -1
else RANKS.index(upcase_card[0,1]) +
10 * ((SUITS.index(upcase_card[1,1]) - trump_index) % 4)
end
end
end

----------------------------------------------------------------

This solution (minus error handling) is also very amenable to
golfing at 187 characters:

.downcase);r="J#{S[x,1]}";l="J#{S[x-2,1]}";puts(t,i.sort_by{|c|
c==r ?-2:c==l ?-1:R.index(c[0,1])+10*((S.index(c[1,1])-x)%4)})

- Warren B.```
on 2005-11-21 20:49
```That is a clever way to sort by suit (trump first), but what happens
on 2005-11-23 02:58
```On Nov 21, 2005, at 2:00 AM, Warren B. wrote:

>     I see other solutions trying very hard to make sure that two suits
> of the same color do not appear next to each other.  As a Euchre
> player,
> I would be quite upset if the order of the suits changed during play.

Hold on there Tiger...  I didn't say anything about changing the suit
order.  We're only working with the initial sort here.

I believe a "correct" implementation caches the initial suit order
for each player and holds that until the hand is played out (even if
black/red suits eventually touch).  Note that you will have to order
the hand twice though, once after the deal and once after Trump is
chosen.

Of course, this is all just *MY* opinion of right.  We've already
heard of several others.  This quiz just isn't about those...  ;)

James Edward G. II```
This topic is locked and can not be replied to.