What's the best way to split this kind of string?

Ruby
1

Hi!

I’m trying to make a routine to make a Morris Number Sequence.
(http://www.ocf.berkeley.edu/~stoll/number_sequence.html)
I need to split a string in the following way, for example.

“111223133” => [“111”, “22”, “3”, “1”, “33”]

I can loop thru the string by each character, comparing with the
previous character.
But is there a quick and easy way?
Probably a regular expression?

Thanks.

Sam

2

Sam K. wrote:

Hi!

I’m trying to make a routine to make a Morris Number Sequence.
(http://www.ocf.berkeley.edu/~stoll/number_sequence.html)
I need to split a string in the following way, for example.

“111223133” => [“111”, “22”, “3”, “1”, “33”]

I can loop thru the string by each character, comparing with the
previous character.
But is there a quick and easy way?
Probably a regular expression?

This seems to work:

“111223133”.scan(/1+|2+|3+|4+|5+|6+|7+|8+|9+|0+/)
=> [“111”, “22”, “3”, “1”, “33”]

–
– Jim W.

3

On Mon, 2006-03-13 at 16:58 +0900, Sam K. wrote:

But is there a quick and easy way?
Probably a regular expression?

Maybe something like:

s.scan(/(\d)(\1*)/).map! { |e| e.join }
# => ["111", "22", "3", "1", "33"]

or:

s.scan(/0+|1+|2+|3+|4+|5+|6+|7+|8+|9+/)
# => ["111", "22", "3", "1", "33"]
4

Sam K. wrote:

But is there a quick and easy way?
Probably a regular expression?

Thanks.

Sam

“111223133”.scan(/(.)(\1*)/).map{|x|x.join}

5

On 3/13/06, Ross B. [email protected] wrote:

Maybe something like:

    s.scan(/(\d)(\1*)/).map! { |e| e.join }
    # => ["111", "22", "3", "1", "33"]

Hmm… Clever

6

On Mon, 13 Mar 2006 17:23:56 +0900, Ross B.
[email protected]
wrote:
[snip]

Maybe something like:

s.scan(/(\d)(\1*)/).map! { |e| e.join }

=> [“111”, “22”, “3”, “1”, “33”]

or:

s.scan(/0+|1+|2+|3+|4+|5+|6+|7+|8+|9+/)

=> [“111”, “22”, “3”, “1”, “33”]

Or:

s.scan(/((.)\2*)/).transpose[0]

Boy, are my fingers glad to save those keystrokes :slight_smile:

andrew