Hi, guys, I am reading the codes for uhd_cal_rx_iq_balance.cpp. When doing calibration by setting the RX and TX antenna as "CAL", is the signal from TX directly switched to RX? And I noticed that in the function set_optimum_defaults(), the tx_gain is 0 but the rx_gain is 25! Is that too high? I heard that when directly connecting TX and RX, we should use attenuators. So why does it set 25 rx_gain? Thanks. Best, Gang
on 2013-01-28 21:23
on 2013-01-28 22:16
Hi, Calibration uses full duplex and should only be done without anything plugged into the 'tx/rx' or 'rx2' ports. There is no direct connection, just measurement of the residual rf escaping. Mike M0MIK
on 2013-01-31 16:48
Hi, Mike, Thanks very much for your reply. I also searched online about the usrp calibration. I found a post and some information: "During cal, the TX is switched away from the TX antenna into the "closed" switch port, where it leaks into the RX which is listening to the TX/RX antenna. So termination on RX2 should have no effect as that port is already unused in calibration." Here is the link: http://lists.ettus.com/pipermail/usrp-users_lists..... I am a little confused. Since calibration uses full duplex, why is there no direct connection between RX2 and TX/RX? I thought they are connected inside the usrp during calibration. Best, Gang
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