Forum: Ruby Insert letters of the alphabet between the original letters of a string

Hi All.

What I seek to realize is that having a particular string, I insert
letters of the alphabet between the letters of the original string.

For example if I have the word: STRING ==> SATBRCIDG
                                            - - - -
This is the code he was doing.

######################################################

a = %w{a b c d e f g h i j k l m n o p q r s t u v w x y z}
str=""

puts "Enter a string:: "
str=gets.chomp.to_s

for i in 0..a.length
  s=cad.insert(i+2, "#{a[i]}")
end

puts s
#########################################################

Thanks.

"STRING".each_char.zip(("A".."Z").cycle).join[0..-2]
#> "SATBRCIDNEG"

Hi,

What's "cad"? It isn't defined anywhere.

Apart from that, the calculation of the indices for insertion is wrong.
You start with 2 instead of 1, and you don't take into account that the
string is growing with each step.

The indices have to be 1, 3, 5, 7, ...


# repeat the characters infintely, because the string may have
# any length
alphabet = ('a'..'z').cycle

string = "String"
0.upto string.length - 2 do |i|
  string.insert 2 * i + 1, alphabet.next
end
puts string


But like I already said in your last thread: Ruby isn't Java. You need
to get rid of this strange "for" loop.

On Thu, Jul 5, 2012 at 1:56 AM, Joao Silva <lists@ruby-forum.com> wrote:
> What I seek to realize is that having a particular string, I insert
> letters of the alphabet between the letters of the original string.

try eg,

> "string".split(//).zip("abcde".split(//)).join
=> "satbrcidneg"

kind regards -botp

On Thu, Jul 5, 2012 at 11:02 AM, botp <botpena@gmail.com> wrote:
>> "string".split(//).zip("abcde".split(//)).join
> => "satbrcidneg"

somehow, this seems readable and easy to type,

> "string".each_char.zip("abcde".each_char).join
=> "satbrcidneg"

kind regards -botp

>
> What I seek to realize is that having a particular string, I insert
> letters of the alphabet between the letters of the original string.
>
> For example if I have the word: STRING ==> SATBRCIDG
>                                             - - - -


I'm surprised no one tried something like this.
Well, not really :)


Not pretty.


s = "STRING"
a = ("a".."z").cycle.take(s.size).join

u = s.size
p (s+a).unpack("a"+("x"*(u-1)+"a"+("X"*u)+"a")*(u-1))*""





Harry

On 07/04/2012 08:27 PM, Hans Mackowiak wrote:
> "STRING".each_char.zip(("A".."Z").cycle).join[0..-2]

I prefer String#chars to String#each_char when not passing a block,
and String#chop to remove the last character.

   "STRING".chars.zip((?A..?Z).cycle).join.chop

Information: cycle and zip does not work on ruby1.8 :D

this works for 1.8;
s="STRING";s.chars.zip(("A".."Z").cycle(s.size)).join.chop

On Thu, Jul 5, 2012 at 5:24 PM, Hans Mackowiak <lists@ruby-forum.com> 
wrote:
> Information: cycle and zip does not work on ruby1.8 :D

info: upgrade. 
http://www.ruby-lang.org/en/news/2011/10/06/plans-for-1-8-7/

best regards -botp

On Thu, Jul 5, 2012 at 6:24 PM, Hans Mackowiak <lists@ruby-forum.com> 
wrote:
> Information: cycle and zip does not work on ruby1.8 :D
>

zip is available for 1.8

Anyway, I think this will work on 1.8 and 1.9

s = "STRING"
a = ("a".."z").to_a

t = s.size-1
t.downto(1).each{|x| s.insert(x,a[x%26-1])}
p s


Harry