hi I amd tanizawa. I had problem. I can not get main.name value from below sql. "find_by_sql 'select main.id,main.name,sub.name from main left join sub on sub.id = main.id'" Please teach me how to get borth name value.
on 2012-06-30 11:09
on 2012-06-30 11:19
On 30 June 2012 10:08, tanizawa <kazuyat7175@gmail.com> wrote: > hi > I amd tanizawa. > > I had problem. > I can not get main.name value from below sql. > "find_by_sql 'select main.id,main.name,sub.name from main left join sub on > sub.id = main.id'" > Please teach me how to get borth name value. My first question would be why are you using find_by_sql? Why not use the normal rails ActiveRecord methods. See http://guides.rubyonrails.org/active_record_querying.html and http://guides.rubyonrails.org/association_basics.html I assume you have already worked through the getting started guide and some tutorials such as railstutorial.org which is free to use online. Colin
on 2012-06-30 15:38
I almost use normal ActiveRecord methods. I use find_by_sql for complected sql. 2012$BG/(B6$B7n(B30$BF|EZMKF|(B 18$B;~(B17$BJ,(B48$BIC(B UTC+9 Colin Law:
on 2012-06-30 16:35
On 30 June 2012 14:37, tanizawa <kazuyat7175@gmail.com> wrote: > I almost use normal ActiveRecord methods. > I use find_by_sql for complected sql. Why are you joining main.id on sub.id? Normally that would be considered poor database design. It would be usual to use a has_one belongs_to relationship, then you could use an ActiveRecord query. Also your table names should be plural to follow the Rails conventions. By the way, please don't top post, it makes it difficult to follow the thread. Insert your reply inline. Thanks. Colin
on 2012-07-01 13:40
On Jun 30, 10:08am, tanizawa <kazuyat7...@gmail.com> wrote: > hi > I amd tanizawa. > > I had problem. > I can not get main.name value from below sql. > "find_by_sql 'select main.id,main.name,sub.name from main left join sub > on sub.id = main.id'" > Please teach me how to get borth name value. Activerecord can't tell the difference between the 2 name columns - you need to give them distinct names e.g. select main.id,main.name,sub.name as sub_name from main ... Fred
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