I am using the following line of code in an action to provide a file
upload capability.
File.open(params[:upload_directory]+'/'+'test1','wb'){|f|
f.write(params[:file2upload].read)}
Admittedly, I'm not real clear on exactly how the above line works;
but, it does work. I'm wondering if there is any way I can get at the
original file name (i.e., the name of the file on the system from
which the file is being uploaded) so that I could substitute it for
'test1' and thereby preserve the original file name.
Any suggestions would be appreciated. Thanks.
... doug
on 2010-03-09 03:57
on 2010-03-09 04:31
Try this:
File.open(File.join(params[:upload_directory],
params[:file2upload].original_filename),'wb'){ |f|
f.write(params[:file2upload].read) }
Jamey
on 2010-03-09 19:47
> Try this: > > File.open(File.join(params[:upload_directory], > params[:file2upload].original_filename),'wb'){ |f| > f.write(params[:file2upload].read) } Yes; but, as I understand your suggestion, that would require me to pass the original filename as a parameter. What I'm trying to find out is whether the original filename is somehow available for use as a part of the file upload mechanism without my having to pass it as a parameter. If it turns out that it's not available within the file upload mechanism; then, I can pass it. It's just that I don't want to go that route if there is an easier way. Thanks for the input. ... doug
on 2010-03-09 20:02
That's what I'm trying to tell you. If you are using a multipart form to upload your file, then the #original_filename attribute should be available on the uploaded file object. Jamey
on 2010-03-09 20:38
> That's what I'm trying to tell you. If you are using a multipart form > to upload your file, then the #original_filename attribute should be > available on the uploaded file object. Got it! I'm an idiot! Thanks a batch. ... doug
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