hi, I want to do a basic thing but without succes: if a=1232, let nb_nb=4 (the number of digits) for i from 1 to nb_nb, I want the following results: i=1 => res=1 (first digit of a) and NOT the number 01 (with a zero in front of the 1) i=2 => res=2 (same thing) i=3 => res=3 i=4 => res=2 I tried a few things, like convert the number in array (it seems to keep the "0" in the result)... do you have a solution? olivier. ___________________________________________________________________________ Yahoo! Mail réinvente le mail ! Découvrez le nouveau Yahoo! Mail et son interface révolutionnaire. http://fr.mail.yahoo.com

on 2009-04-30 15:55

on 2009-04-30 16:38

You could try a.to_s.split(//).collect {|s| s.to_i} and extract nb_nb elements. Bob Schaaf

on 2009-04-30 16:58

Olivier L. wrote: > hi, > > I want to do a basic thing but without succes: > if a=1232, let nb_nb=4 (the number of digits) > for i from 1 to nb_nb, I want the following results: > i=1 => res=1 (first digit of a) and NOT the number 01 (with a zero in > front of the 1) > i=2 => res=2 (same thing) > i=3 => res=3 > i=4 => res=2 > > I tried a few things, like convert the number in array (it seems to keep > the "0" in the result)... > > do you have a solution? > It's not clear to me what you want to do, but maybe this will help: a=1232 str = a.to_s p str --output:-- "1232" digits = [] str.length.times do |i| digits << str[i, 1] end p digits --output:-- ["1", "2", "3", "2"] > res=1 (first digit of a) and NOT the number 01 1 and 01 are the same *number*.