The “Ruby_RegularExpression” sample application in the
javapassion rubyonrails tutorial has this code
puts “----Regular Expression”
puts a = “hello there”
puts a[1] #=> 101
puts a[1,3] #=> “ell”
How do you get 101 from a[1]
The “Ruby_RegularExpression” sample application in the
javapassion rubyonrails tutorial has this code
puts “----Regular Expression”
puts a = “hello there”
puts a[1] #=> 101
puts a[1,3] #=> “ell”
How do you get 101 from a[1]
On Apr 16, 2009, at 6:40 PM, Reg wrote:
The “Ruby_RegularExpression” sample application in the
javapassion rubyonrails tutorial has this codeputs “----Regular Expression”
puts a = “hello there”
puts a[1] #=> 101
puts a[1,3] #=> “ell”How do you get 101 from a[1]
It’s the value associated with the character e in ASCII.
In irb:
RUBY_VERSION
=> “1.8.6”a = ‘hello’
=> “hello”
a[1]
=> 101
?e
=> 101
a[1 ,1]
=> “e”
If you look at the ri documnetation for String#[] in Ruby 1.8.6 you
can see:
Element Reference---If passed a single +Fixnum+, returns the code
of the character at that position.
[…]
In Ruby 1.9 things change so that you always get a String or nil back
from String#[]:
irb(main):001:0> RUBY_VERSION
=> “1.9.2”
irb(main):002:0> a = ‘hello’
=> “hello”
irb(main):003:0> a[1]
=> “e”
irb(main):004:0>
Hope this helps,
Mike
–
Mike S. [email protected]
http://www.stok.ca/~mike/
The “`Stok’ disclaimers” apply.
On Thu, 16 Apr 2009 18:02:52 -0500, Mike S. [email protected] wrote:
a[1]
of the character at that position.
=> “e”
irb(main):004:0>Hope this helps,
Mike
Its a great help!
Thanks Mike
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